Building time :
4c + 6a < = 120
testing time :
4c + 4a < = 100
20 child bikes and 6 adult bikes...c = 20 and a = 6
sub into both equations
4c + 6a < = 120
4(20) + 6(6) < = 120
80 + 36 < = 120
116 < = 120 (correct)
4c + 4a < = 100
4(20) + 4(6) < = 100
80 + 24 < = 100
104 < = 100 (incorrect)
ur answer : No, because the bike order does not meet the restrictions of 4c + 6a < = 120 and 4c + 4a < = 100
Answer:
B
Step-by-step explanation:
Answer:
Option A is correct.
The given expression :
then;

Step-by-step explanation:
Given the expression: 
Cross multiplication the given expression following steps are as follow;
- Multiply numerator of the left-hand fraction by the denominator of the right-hand fraction
- Also, Multiply numerator of the right-hand fraction by the denominator of the left-hand fraction.
- then, set the two products equal to each other.
Using cross multiplication, on the given expression;

First multiply the numerator of the left hand fraction(i.e,a ) by the denominator of the right hand fraction (i,e a)
we have;

Simplify:
[1]
now, multiply numerator of the right-hand fraction( i.e, 9) by the denominator of the left-hand fraction (i.e, 4 ) in [1]
we have;

Simplify:

Therefore, the given expression is equal to: 
9514 1404 393
Answer:
zero solutions
Step-by-step explanation:
The first inequality has a boundary line with a slope of 3 and a y-intercept of 9. Shading is above the boundary line.
The second inequality has a parallel boundary line with a slope of 3 and a y-intercept somewhat lower, at -1. Shading is below this boundary line.
There is a gap between the shaded areas, so no points will be solutions to both inequalities.