Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
There is allways 4 ounces in 1 pint.
Answer:
100
Step-by-step explanation:
since its collinear it has to be 180 -80 which equals 100.
Answer:
Step-by-step explanation:
The length of the midsegment is half of the base in this case.
12x = 8x + 40
4x=40
x=10
So it's 60
