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ladessa [460]
3 years ago
9

Bob sold 34 trading cards, each for 50 cents more than the price he bought them. If each card was originally $0.25, how much did

he earn?​
Mathematics
1 answer:
Naya [18.7K]3 years ago
3 0

Answer:

E/A card was sold for $.75, which means the 34 cards were sold for a total of $25.50

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If sin =1/2then show that 3cos -4cos^3=0z
Katarina [22]

Step-by-step explanation:

ever coner should have a value.... for example sinA or cos$

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3 years ago
a buret is a tool designed to transfer precise amounts of liquid .A buret initially contains 70.00 millimeters of a solution and
katrin [286]

Let:

Vbu= Volume of the buret

Vbk= Volume of the beaker

A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:

x = Number of drips

a = volume of each drip

\begin{gathered} Vbu=70-ax \\ Vbk=20+ax \\ \text{where:} \\ a=0.05 \\ Vbu=70-0.05x \\ Vbk=20+0.05x \end{gathered}

after how many drips will the volume of the solution in the buret and beaker be equal ?​ Vbu = Vbk:

\begin{gathered} Vbu=Vbk \\ 70-0.05x=20+0.05x \\ \text{Solve for x:} \\ 0.1x=70-20 \\ 0.1x=50 \\ x=\frac{50}{0.1} \\ x=500 \end{gathered}

5 0
1 year ago
On 1st January 2020, Laurie invests P dollars in an account that pays a nominal annual interest rate of 5.5%, compounded quarter
andrezito [222]

Answer:

1) The common ratio =  1.055

2) The year in which the amount of money in Laurie's account will become double is the year 2032

Step-by-step explanation:

1) The given information are;

The date Laurie made the investment = 1st, January, 2020

The annual interest rate of the investment = 5.5%

Type of interest rate = Compound interest

Therefore, we have;

The value, amount, of the investment after a given number of year, given as follows;

Amount in her account = a, a × (1 + i), a × (1 + i)², a × (1 + i)³, a × (1 + i)ⁿ

Which is in the form of the sum of a geometric progression, Sₙ given as follows;

Sₙ = a + a × r + a × r² + a × r³ + ... + a × rⁿ

Where;

n = The number of years

Therefore, the common ratio = 1 + i = r = 1 + 0.055 = 1.055

The common ratio =  1.055

2) When the money doubles, we have;

2·a = a × rⁿ = a × 1.055ⁿ

2·a = a × 1.055ⁿ

2·a/a = 2 = 1.055ⁿ

2 = 1.055ⁿ

Taking log of both sides gives;

㏒2 = ㏒(1.055ⁿ) = n × ㏒(1.055)

㏒2 = n × ㏒(1.055)

n = ㏒2/(㏒(1.055)) ≈ 12.95

The number of years it will take for the amount of money in Laurie's account to double = n = 12.95 years

Therefore, the year in which the amount of money in Laurie's account will become double = 2020 + 12..95 = 2032.95 which is the year 2032

The year in which the amount of money in Laurie's account will become double = year 2032.

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harkovskaia [24]

Answer: -75

Step-by-step explanation:

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2 years ago
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Without any transformations (up or down), the range is y > 0
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