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IgorC [24]
3 years ago
14

Darius needs to solve 45 math problems for his homework assignment. He already completed 15 of the problems in morning study hal

l. He then worked from 3:15 to 4:30 to
complete the remainder of the problems. How many minutes does it take Darius to complete one problem?
Answer
A) 2/5 minute
B) 1 1/4minutes
С) 1 2/3minutes
D) 2 1/2minutes
Mathematics
2 answers:
AleksAgata [21]3 years ago
3 0

Answer:

its c

Step-by-step explanation:

its C because 3;15 through 4:30  is already a 1hr and is you subtract 3-1 is gonna give you 2 but if that not enough i best advise to elimanate a and d

scoray [572]3 years ago
3 0

Answer:

Option D: 2\frac{1}{2} minutes is the correct answer.

Step-by-step explanation:

Given that:

Darius needs to solve 45 math problems. He as already solved 15 problems.

Remaining problems to be solved = Total - Already solved

Remaining problems = 45-15 = 30 problems

Time worked = 3:15 to 4:30 = 75 minutes

Darius have 75 minutes to solve 30 problems.

Time for one problem = \frac{remaining\ problems\ to\ solve}{time\ worked}

Time for one problem = \frac{75}{30} = \frac{5}{2}\ minutes

Time for one problem = 2\frac{1}{2}\ minutes

It takes Darius 2\frac{1}{2} minutes to complete one problem.

Hence,

Option D: 2\frac{1}{2} minutes is the correct answer.

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kobusy [5.1K]

Answer:

15.2\ units

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

P=AB+BC+CD+DE+AE

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 2

<em>Find the distance AB</em>

A(-2, 1). B(-3, 3)

substitute in the formula

d=\sqrt{(3-1)^{2}+(-3+2)^{2}}

d=\sqrt{(2)^{2}+(-1)^{2}}

d_A_B=\sqrt{5}=2.24\ units

step 3

<em>Find the distance BC</em>

B(-3, 3), C(-1, 5)

substitute in the formula

d=\sqrt{(5-3)^{2}+(-1+3)^{2}}

d=\sqrt{(2)^{2}+(2)^{2}}

d_B_C=\sqrt{8}=2.83\ units

step 4

<em>Find the distance CD</em>

C(-1, 5), D(2, 4)

substitute in the formula

d=\sqrt{(4-5)^{2}+(2+1)^{2}}

d=\sqrt{(-1)^{2}+(3)^{2}}

d_C_D=\sqrt{10}=3.16\ units

step 5

<em>Find the distance DE</em>

D(2, 4),E(2, 1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(2-2)^{2}}

d=\sqrt{(-3)^{2}+(0)^{2}}

d_D_E=\sqrt{9}\ units

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step 6

<em>Find the distance AE</em>

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substitute in the formula

d=\sqrt{(1-1)^{2}+(2+2)^{2}}

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step 7

Find the perimeter

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substitute the values

P=2.24+2.83+3.16+3+4=15.23\ units

Round to the nearest tenth of a unit

P=15.2\ units

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