Answer: 50a+2
Step-by-step explanation:
1. Simplify 5a5a\5a5a to 1.
1+5×10a+10
2.Simplify 5×10a to 50a.
1+50a+10
3.Cancel 10.
1+50a+1
4. Collect like terms.
50a+(1+1)
5. Simplify.
50a+2
Given the position function, the velocity function is obtained by taking the derivative:

The velocity is increasing its own derivative is positive, so we also have to find the acceleration by taking another derivative:

To find when
, we first need to know where
:

The quadratic factor is always positive (its discriminant is negative), which leaves one solution at
. To either side of
, we have, for instance,


which indicates that
is increasing for
, making the answer A.
Answer:
-3 is the value of k in g(x)=kf(x)
Step-by-step explanation:
Both functions cross nicely at x=-3 so I'm going to plug in -3 for x:
g(x)=kf(x)
g(-3)=kf(-3)
To solve this for k we will need to find the values for both g(-3) and f(-3).
g(-3) means we want the y that corresponds to x=-3 on the curve/line of g.
g(-3)=-3
f(-3) means we want the y that corresponds to x=-3 on the curve/line of f.
f(-3)=1
So our equation becomes:
g(-3)=kf(-3)
-3=k(1)
-3=k
So k=-3.
Answer:
600
Step-by-step explanation:
105/7 * x/40
7x=4,200
x=600