Solve 6b<24 or 4b+12>4
1 answer:
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Answer: option d. x = 3π/2
Solution:
function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
Solution:
function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
Let N be the number of items sold and p the price.
Since the variation is inverse, then the relation between N and p is:
For N=20000 and p = $9.5, we get the formula:
If p = 8.75, then the number of items sold can be computed using the formula:
Since the variation is inverse, then the relation between N and p is:
For N=20000 and p = $9.5, we get the formula:
If p = 8.75, then the number of items sold can be computed using the formula:
Answer:
Step-by-step explanation:
Red:black = 1:1
Red cards = x
Black cards =x
x + x = 48
2x = 48
x = 48/2
x = 24
No. of red cards = 24
No of black cards = 24
Now 8 red cards are removed
So, No. of red cards = 24 - 8 =16
Red: Black = 16:24
Red: Black = 2:3