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Rom4ik [11]
3 years ago
8

Find slope in y=-5/2x-5

Mathematics
1 answer:
Tems11 [23]3 years ago
5 0

Answer:

slope = -5/2

Step-by-step explanation:

We know that slope intercept form is y=mx+b where m is the slope.

We see in the equation that -5/2 is m.

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Enter the number in scientific notation.<br> 0.00153<br> =<br><br> x 10
Korolek [52]

Answer:

15.3 x 10^-4

Step-by-step explanation:

3 0
3 years ago
If y varies inversely as x, and y = 58 when x = 9, find y when x = 261.
Umnica [9.8K]

Answer:

2

Step-by-step explanation:

y=k/x

58=k/9

k=58×9

k=522

y=522/x

when x=261

y=522/261

y=2

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3 years ago
Angles R and Z are complementary. If m ∠R = 26˚, what is the measure of angle Z?
zysi [14]

Answer:

64

Step-by-step explanation:

(note:Two angles are called complementary when their measures add to 90 degrees.)

90-26=64

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Annette [7]

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Step-by-step explanation:

6 0
3 years ago
Determine the equation of the tangent of the hyperbola that is parallel to the given line:
marin [14]

The tangent line to the curve has slope equal to \frac{\mathrm dy}{\mathrm dx}. Use implicit differentiation to find this derivative.

9x^2-4y^2=32

\implies18x-16y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{-18x}{-16y}=\dfrac{9x}{8y}

The given line in slope-intercept form is

9x+2y-1=0\implies y=\dfrac{1-9x}2

and has slope -9/2. Any line parallel to this one has the same slope. The tangent to the hyperbola has this slope at points (<em>x</em>, <em>y</em>) such that

-\dfrac92=\dfrac{9x}{8y}\implies x=-4y

Find the points on the hyperbola where this condition is met.

9(-4y)^2-4y^2=140y^2=32\implies y^2=\dfrac{32}{140}\implies y=\pm\sqrt{\dfrac8{35}}\implies x=\pm4\sqrt{\dfrac8{35}}

Then use the point-slop formula to build the equations of these tangents:

y\mp\sqrt{\dfrac8{35}}=-\dfrac92\left(x\pm4\sqrt{\dfrac8{35}}\right)

8 0
3 years ago
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