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VikaD [51]
3 years ago
7

Help!!!!!!!!!!!!————

Mathematics
1 answer:
Annette [7]3 years ago
6 0

Answer :Could you take a better photo? I dont quite understand what needs to be found there

Step-by-step explanation:

You might be interested in
Lavania is studying the growth of a population of fruit flies in her laboratory. After 6 days she had nine more than five times
MatroZZZ [7]

Answer:

Lavania observed 39 fruit flies after 6 days of observation

Step-by-step explanation:

Let x be the number of fruit flies on the first day of Lavania's study.

After 6 days she had nine more than five times as many fruit flies as when she began the study.

Five times as many fruit flies as when she began the study = 5x

Nine more than five times as many fruit flies as when she began the study=5x+9

The expression to find the population of fruit flies Lavania observed after 6 days is 5x+9

If she observes 20 fruit flies on the first day of the study, then x=6, then

5x+9=5\cdot 6+9=30+9=39

5 0
3 years ago
PLEASE HELP!!!! Identify the mistake and use the correct answer to the problem!!!
Tems11 [23]

Answer:

1 \frac{3}{8}

Step-by-step explanation:

the denominators must be the same so, since 4 goes evenly into 24 we can create an equivalent fraction from 3/4 to 18/24 (multiply numerator and denominator by 6)

now you can add:

\frac{15}{24} + \frac{18}{24} = \frac{(15+18)}{24} = \frac{33}{24}

since the numerator is larger than the denominator this is called an improper fraction and can be changed into a mixed number by dividing 24 into 33

24 goes into 33 one time with a remainder of 9

so 33/24 = 1 \frac{9}{24} wherein 9 and 24 can each have a 3 factored out to make it fully simplified

9÷3 = 3

24÷3 = 8

final answer is 1 \frac{3}{8}

6 0
2 years ago
Read 2 more answers
You have relatives living in the United Kingdom and in France. Suppose that you have purchased a prepaid phone card with a value
maxonik [38]

Answer:

a) 0.23x+0.21y=75

b) (For the Graph see the attached picture).

A possible solution for the inequality 0.23x+0.21y\leq75 would be any point inside the shaded region of the graph. For example (150,175) This is 150 minutes to the United Kingdom and 175 minutes to France.

0.23x+0.21y\leq75

0.23(150)+0.21(175)\leq75

34.5+36.75\leq75

71.25\leq 75

this inequality is true, so the number of minutes used for the United Kingdom and to France is valid.

Step-by-step explanation:

a)

In order to solve this problem, we must first set our variables:

x= Minutes to the United Kingdom.

y= Minutes to France

The greatest amount of money you can spend is $75 and each minute will cost $0.23 when calling to the United Kingdom and $0.21 when calling to France. So we can use this information to build our equation:

0.23x+0.21y=75.

b) So first, we need to convert our equation into an inequality where the total amount of money spent must be less than $75, so our inequality is:

[tex}0.23x+0.21y\leq75[/tex]

so now we can proceed and graph. This is graphed exactly as you would graph a regular linear equation. You need to find two points on the graph that will satisfy the equation. Plot them and then connect them with a straight line. For example:

First, let's solve the equation for y:

0.23x+0.21y=75

we start by moving the 0.23x to the other side of the equation so we get:

0.21y=-0.23x+75

and next we divide both sides of the equation into 0.21 so we get:

y=\frac{-0.23x+75}{0.21}

which yields:

y= -1.095x+357.14

next we need to pic an x-value so we can find the first ordered pair. Let's say I pick x=0. So we get:

y= -1.095x+357.14

y= -1.095(0)+357.14

y=357.14

so our first point is (0, 357.14)

And we can follow the same procedure for the second point. Let's say I pick x=1. In that case our second point is (1, 354.04). We can now plot them. Once the graph is drawn, we need to shade it, for which we will pick an ordered pair to the left and an ordered pair to the right of the line. For the left region let's pick the point (0,0) and for the right of the graph, let's pick the point (150,357).

So let's test the inequality for these two points:

First, let's use the point (0,0)

0.23x+0.21y\leq75

0.23(0)+0.21(0)\leq75

0\leq75

This proves that the left side of the graph is the side to be shaded. We can still use the other point and see what we qet:

(150, 357) and let's use it on our inequality:

0.23x+0.21y\leq75

0.23(150)+0.21(357)\leq75

109.47\leq75

Is a false statement, so only the region on the left will contain the possible number of minutes to do the phone calls to the UK and France.

A possible solution for the inequality 0.23x+0.21y\leq75 would be any point inside the shaded region of the graph. For example (150,175) This is 150 minutes to the United Kingdom and 175 minutes to France.

0.23x+0.21y\leq75

0.23(150)+0.21(175)\leq75

34.5+36.75\leq75

71.25\leq 75

This is a true statement so the possible solution is correct.

6 0
3 years ago
Working alone, Henry takes 3 hours less than Mary to clean the carpets in the entire office. Working together, they can clean th
Sati [7]

Answer:

It would take Henry 3 hours to clean the office carpets if Mary were not there to help

Step-by-step explanation:

Assume that it takes Henry t hours to clean the carpets

∵ Henry takes 3 hours less than Mary to clean the carpets

∵ Henry takes t hours

- That means add 3 to t to find Mary time

∴ Mary takes t + 3 hours

∵ The rate of Henry is \frac{1}{t}

∵ The rate of Mary is \frac{1}{t+3}

∵ Working together, they can clean the carpets in 2 hours

- Add the two rates and equate the answer by \frac{1}{2} (their rate together)

∴ \frac{1}{t}+\frac{1}{t+3}=\frac{1}{2}

Multiply the two denominators and multiply each numerator by the other denominator to add the two fractions of the left hand side

∵ \frac{(1)(t+3)}{t(t+3)}+\frac{(1)t}{t(t+3)}=\frac{1}{2}

∴  \frac{(t+3)}{t(t+3)}+\frac{t}{t(t+3)}=\frac{1}{2}

- Add the two fractions in the left hand side

∴ \frac{t+3+t}{t(t+3)}=\frac{1}{2}

∴  \frac{2t+3}{t^{2}+3t}=\frac{1}{2}

Use the cross multiplication

∵ (t² + 3t)(1) = 2(2t + 3)

∴ t² + 3t = 4t + 6

- Subtract 4t from both sides

∴ t² - t = 6

- Subtract 6 from both sides

∴ t² - t - 6 = 0

- Factorize it into two factors

∴ (t - 3)(t + 2) = 0

Equate each factor by 0 to find t

∵ t - 3 = 0

- Add 3 to both sides

∴ t = 3

OR

∵ t + 2 = 0

- Subtract 2 from both sides

∴ t = -2 ⇒ reject this answer because there is no - ve time

∴ t = 3

∴ Henry would take 3 hours to clean the carpets alone

It would take Henry 3 hours to clean the office carpets if Mary were not there to help

8 0
3 years ago
A pair of equations is shown below:
Margarita [4]

<em><u>your </u></em><em><u>question</u></em><em><u>:</u></em><em><u> </u></em>

A pair of equations is shown below:

y = 7x − 9

y = 3x − 1

Part A: In your own words, explain how you can solve the pair of equations graphically. Write the slope and y-intercept for each equation that you will plot on the graph to solve the equations. (6 points) YOU HAVE ALREADY ANSWERED

Part B: What is the solution to the pair of equations? (4 points)

<em><u>answer:</u></em><em><u> </u></em>

<em>t</em><em>he </em><em>solution </em><em>to </em><em>the </em><em>pair </em><em>of </em><em>equations </em><em>would </em><em>be </em>

(2,5)

<em><u>how </u></em><em><u>do </u></em><em><u>we </u></em><em><u>get </u></em><em><u>this</u></em><em><u>?</u></em>

<em> </em><em>you </em><em>put </em><em>both </em><em>equations </em><em>in </em><em>a </em><em>desmos </em><em>graphing </em><em>calculator</em><em> </em>

<em>hope </em><em>this </em><em>helps,</em><em> </em><em>have </em><em>a </em><em>great </em><em>night </em><em>:</em><em>)</em><em> </em>

4 0
3 years ago
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