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2 years ago

Find the value of each determinant

Mathematics

1 answer:

Ksenya-84 [330]2 years ago

6 0

Answer:

−4304

Step-by-step explanation:

1. The given determinant is :

$\begin{vmatrix}7 &31 \\ 142& 14\end{vmatrix}$

We need to find its determinant . It can be solved as follows :

$\begin{vmatrix}7 &31 \\ 142& 14\end{vmatrix}=7(14)-142(31)\\\\=-4304$

So, the value of determinant is equal to −4304.

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mr_godi [17]

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2 years ago

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$To \; find \; the \; maximum \; number \; of \; items \; possible \; in each \; packet,\\we \; need \; to \; find \; the \; Greatest \; Common \; Factor\\ \; of \; 527 \; Pencils, \; 646 \; erasers \; and \; 748 \; sharpeners.\\\\We \; need \; to \; list \; the \; Factors \; of \; each \; number \; as \; given \; below\\ \; and \; identify \; the \; greatest \; common \; factor.$

$The \; factors \; of \; 527 \; are:\\1, \; 17, \; 31, \; 527\\\\The \; factors \; of \; 646 \; are:\\1, \; 2, \; 17, \; 19, \; 34, \; 38, \; 323, \; 646\\\\The \; factors \; of \; 748 \; are:\\1, \; 2, \; 4, \; 11, \; 17, \; 22, \; 34, \; 44, \; 68, \; 187, \; 374, \; 748\\\\Then \; the \; greatest \; common \; factor \; is \; 17.$

$Conclusion: \\There \; will \; 31 \; Pencils, \; 38 \; Erasers,\\ \; and \; 44 \; Sharpeners \; in \; each \; of \; SEVENTEEN \; packet.$

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