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mars1129 [50]
3 years ago
5

On a 1-mile walking tour of New York City, a group had to take a detour that was 100 yards shorter than half the distance of the

tour. The detour is how many yards long?
Thanks!
Mathematics
1 answer:
Goryan [66]3 years ago
4 0
One second, I can do it
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A coat of paint of thickness 0.06 cm is to be applied uniformly to the faces of a cube of edge 33 cm. Use differentials to find
Aneli [31]

Answer:

392 cm^3

Step-by-step explanation:

Let X represent the edge of a cube

let t represent the thickness of the paint.

Volume of a cube = x^3

V = x^3

Differentiate V with respect to x

dV/dx = 3x^2

dV = 3x^2 dx

dx = 2dt

= 2(0.06)

= 0.12

dV = 3(33)^2 (0.12)

dV = 392.04cm^3

dV = 392 cm^3

6 0
3 years ago
What is the distance between points V(3, 3) and W(–2, –3)?
Brut [27]

Answer:

√61

Step-by-step explanation:

6 0
3 years ago
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Two sides of a triangle have the following measures. Find the range of possible measures for the third side.
Bond [772]

Answer:

x=14.3

Step-by-step explanation:

its the Pythagorean theorem

3 0
3 years ago
Does anybody know the answer to these questions?
san4es73 [151]

Answer:

  1. 625,000 J

  2. 100 J

  4. 5 kg

  5. √5 ≈ 2.236 m/s

Step-by-step explanation:

You should be aware that the SI derived units of Joules are equivalent to kg·m²/s².

To reduce confusion between <em>m</em> for mass and m for meters, we'll use an <em>italic m</em> for mass.

In each case, the "find" variable is what's left after we put the numbers into the formula. It is what the question is asking for. The "given" values are the ones in the problem statement and are the values we put into the formula. The formula is the same in every case.

__

1. KE = (1/2)<em>m</em>v² = (1/2)(2000 kg)(25 m/s)² = 625,000 kg·m²/s² = 625,000 J

__

2. KE = (1/2)<em>m</em>v² = (1/2)(0.5 kg)(20 m/s)² = 100 kg·m²/s² = 100 J

__

4. KE = (1/2)<em>m</em>v²

  250 J = (1/2)<em>m</em>(10 m/s)² = 50 m²/s²

  (250 kg·m²/s²)/(50 m²/s²) = <em>m</em> = 5 kg

__

5. KE = (1/2)<em>m</em>v²

  2000 kg·m²/s² = (1/2)(800 kg)v²

  (2000 kg·m²/s²)/(400 kg) = v² = 5 m²/s²

  v = √5 m/s ≈ 2.236 m/s

7 0
3 years ago
How to find equation of line passing through the points (x,y)​
DochEvi [55]

First you must acknowledge that you are dealing with a line therefore you must write linear equation or linear function in this case.

Linear function has a form of,

y=mx+n

Then calculate the slope <em>m</em> using the coordinates of two points. Let say <em>A(x1, y1)</em> and <em>B(x2, y2)</em>,

m=\dfrac{\Delta{y}}{\Delta{x}}=\dfrac{y_2-y_1}{x_2-x_1}

Now pick a point either <em>A</em> or <em>B</em> and insert coordinates of either one of them in the linear equation also insert the slope you just calculated, I will pick point <em>A</em>.

y_1=mx_1+n

From here you solve the equation for n,

y_1=mx_1+n\Longrightarrow n=y_1-mx_1

So you have slope <em>m</em> and variable <em>n</em> therefore you can write down the equation of the line,

f(x)=m_{slope}x+n_{variable}

Hope this helps.

r3t40

3 0
3 years ago
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