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alexira [117]
3 years ago
11

Does anyone know what the vertex is?

Mathematics
1 answer:
sveticcg [70]3 years ago
7 0

Answer:

A vertex (or node) of a graph is one of the objects that are connected together. The connections between the vertices are called edges or links. A graph with 10 vertices (or nodes) and 11 edges (links). For more information about graph vertices, see the network introduction.

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Triangle ABC has vertices A(0, 4), B(2, 1), and C(4, 3). Find the
dmitriy555 [2]
A(0,-4)
B(2,-1)
C(4,-3)
6 0
3 years ago
The face of a clock is divided into 12 equal parts. The radius of the clock face is 6 inches. Assume the hands of the clock will
irina [24]
<h2>Answer:</h2><h2>Option (i),(iii), (v) are correct</h2>

Step-by-step explanation:

Given, the face of a clock is divided into 12 equal parts.

Angle of each part = \frac{360}{12} = 30°

(i) When one hand points at 2 and the other points at 4, this is can be divided into two parts, 2 to 3 and 3 to 4.

The angle formed = 2 (30) = 60°

Option (i) is correct

(ii) The circumference of the clock is ,

Circumference of circle = 2πr,

where r is the radius = 6 and π = 3.14.

Substituting the values in the formula, we get

Circumference of circle = 37.68.

Option (ii) is wrong.

(iii) With one hand at 5 and the other at 10, this is 5 parts

The angle formed= 30(5) = 150°.  

The arc length =\frac{150}{360}(37.68) = 15.7

Option (iii) is correct

(iv) When one hand points at 1 and the other points at 9, this is 4 parts,

30(4) = 120°.  T

Option (iv) is wrong

(v) The length of the minor arc from 11 to 2, this is 3 parts

3(30) = 90°  

minor arc from 7 to 10 is 3(30) = 90°  

Option (v) is correct

6 0
3 years ago
Read 2 more answers
Factor. 10 x ^5 −16 x^ 4 +4 x^ 2 Enter your answer in the box.
pshichka [43]

10x^5 - 16x^4 + 4x^2

Factor out what they have in common: 2 and x^2

2x^2(5x^3 - 8x^2+2)

3 0
3 years ago
Read 2 more answers
Two litters of a particular rodent species have been born, one with two brownhaired and one gray-haired (litter 1), and the othe
anyanavicka [17]

Answer:

a. So probability that the animal chosen is brown-haired = 0.633

b. Given that a brown-haired offspring was selected, probability that the sampling was from litter1 = P(B|A) = 0.5263.

Step-by-step explanation:

Being that We are given,event of Brown hair with two disjoint events, one is { ( BrownHair ) ∩ ( Litter 1) } and the other is { ( BrownHair ) ∩ ( Litter 2) } .

a) To find the probability that the animal chosen is brown-haired,

Let A : we choose a brown-haired rodent and B : we choose litter1.

So using the axioms of probability, we can write

P(A) = P(A | B) * P(B) + P(A | Bc) * P(Bc)

Making use of the given information, we get;

number of brown haired rodents in litter 2 P(AB) Total number of rodents in litterl

and

P(A |B^{c}) =\frac{\text{number of brown haired rodents in litter2}}{\text{Total number of rodents in litter2}}= \frac{3}{5}

And also it is given that we choose litter at random ,so P(B) = P(Bc ) = 1/2

So now we plug these values in the equation of P(A) and get

P(A) = (\frac{2}{3}*\frac{1}{2}) + (\frac{3}{5}*\frac{1}{2}) = \frac{2}{6}+\frac{3}{10} = 0.633

So probability that the animal chosen is brown-haired = 0.633

b) Given that a brown-haired offspring was selected, probability that the sampling was from litter1 = P(B|A)

Lets make use of Bayes rule to find this conditional probability,

So using theorem we get,

P(B|A) = \frac{P(A|B)*P(B)}{P(A|B)*P(B)+P(A|B^{c})*P(B^{c})}

P(B|A) = \frac{(1/2)*(2/3)}{[(1/2)*(2/3)]+[(1/2)*(3/5)]} = \frac{10}{19} = 0.5263

Thus, Given that a brown-haired offspring was selected, probability that the sampling was from litter1 = P(B|A) = 0.5263.

5 0
3 years ago
Help Please on this question
Anika [276]

Answer:

See below

Step-by-step explanation:

According to triangle mid-segment theorem:

c) CT = 1/2 EN

Given that EN = 43

=> CT = 1/2 (43)

=> CT = 21.5

a) AE = 2PT

Since PT = 13

=> AE = 2(13)

=> AE = 26

b) AN = 2CP

Given that CP = 29

=> AN = 2(29)

=> AN = 58

d) Perimeter of AEN = AE + EN + AN

P = 26 + 43 + 58

P = 127

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
7 0
2 years ago
Read 2 more answers
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