Answer:
x = 0
Step-by-step explanation:
Finding the upper and lower bounds for a definite integral without an equation is pretty hard because how can we find the upper and lower bounds of definite integral if there is no equation given. But I will teach you how to find the lower and upper bounds of a definite integral, when the equation is like this
So, i integrate this,

I know I have a minimum at x=3 because;
f(t )= t^2 − 6t + 11
f′(t) = 2
t−6 = 0
2(t−3) = 0
t = 3
f(5) = 4
f(1) = −4
Lateral area = surface area <em>not including</em> the bases.
To find this area we just need to add up the area of all of those sides.
The 2 bases are the same area and defined by the length and width.
That leaves the 2 sides defined by length and height,
plus the 2 defined by width and height.
Of course, to find the area of a rectangle, we just multiply together its two dimensions.
length × height = 14 × 6 = 84
width × height = 9 × 6 = 54
2 × 84 + 2 × 54 = 276 m²
Answer:
(2,3)
Step-by-step Explanation:
2x - y = 1
-y = -2x + 1
y = 2x - 1
4x + y = 11
4x + 2x -1 = 11
6x = 12
x=2
y=2x-1
y=2(2)-1
y=3
Answer:
PR = 15
Step-by-step explanation:
PR = PQ + QR
10x - 45 = 3 + x + 6 {Combine like terms}
10x - 45 = 9 + x {Subtract 'x' from both sides}
10x - x - 45 = 9
9x - 45 = 9 {Add 45 to both sides}
9x = 9 +45
9x = 54
x = 54/9
x = 6
PR = 10x - 45
= 10*6 - 45
= 60 - 45
PR = 15