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3 years ago

Classify a triangle whose side lengths are 8, 16, and 18

Mathematics

1 answer:

Lostsunrise [7]3 years ago

4 0

Answer:

Obtuse triangle

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as right angled, acute, obtuse and isosceles triangle.

In right angle triangle, one angle is 90°. The square of the longest side (hypotenuse) is equal to the sum of the square of the two sides.

An acute triangle is a triangle with acute angles (less than 90°). The square of the longest side is less than the sum of the square of the two sides.

An obtuse triangle is a triangle with one obtuse angle (greater than 90°) and two acute angles (less than 90°). The square of the longest side is larger than the sum of the square of the two sides.

An isosceles triangle is a triangle with two equal sides.

Given a triangle whose side lengths are 8, 16, and 18, the longest side is 18.

Since no two sides are the same hence it is not an isosceles triangle.

Also, 18² > 16² + 8²; therefore this is an obtuse triangle

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Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be . Saul asks Jasmine

Amiraneli [1.4K]

The question is incomplete. The compete question is :

Saul decides to use the IQR to measure the spread of data. Saul calculates the IQR of the data set to be 27. Saul asks Jasmine to check his work. Saul copies the data in numerical order from least to greatest for Jasmine. 25, 30, 50, 50, 50, 50, 56, n, 250. What is the value of n that will make the IQR of the data set equal to 27?

Solution :

The inter quartile range is being measured as : 3rd quartile - 1st quartile

The 1st quartile = 25% mark

The 3rd quartile = 75% mark

The data set as given in the question is :

25, 30, 50, 50, 50, 50, 56, n, 250

Therefore, the total number of the sample = 9

And the median is = 50

The median separates the given data sets into two equal halves-- that is the upper half and the lower half.

Let the middle of a lower half is the 1st quartile be $Q_1$

And the middle of a 2nd half is the 3rd quartile be $Q_3$

∴ $Q_1=\frac{30+50}{2}$

$=40$

$Q_3=\frac{56+n}{2}$

Now for the IQR of the data set to be equal to $27$ ,

$\frac{56+n}{2}-40=27$

$\frac{56+n}{2}=27+40$

$\frac{56+n}{2}=67$

$56 +n=134$

$n=134-56$

$n=78$

4 0

3 years ago

3+2−16⋅9=?<br> can you help me

wel

-99..?? I think that’s the answer

7 0

3 years ago

Read 2 more answers

determine the value of x for which r parallels s. then find the measure of angle 1 and the measure of angle 2measure angle 1= 50

Maslowich

According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.

$\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}$

x is 3/2. Replace this value in both expression to find the measure of each angle.

$\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}$

The measure of these angles is 47°

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2 years ago

The daily cost of producing x high performance wheels for racing is given by the following function, where no more than 100 whe

WINSTONCH [101]

So all you need to do if find the min of the function:

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3 years ago

If you worked for 6 days for a total of 67.8 hours. If I worked the same number of hours each day, how many hours did I work in

Hunter-Best [27]

Hi there!

To solve this problem, we need to divide 67.8 by 6 to find the amount of hours each day.

67.8 / 6 = 11.3

You worked 11.3 hours each day.

Hope this helps!

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3 years ago