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3 years ago

6

Unbalanced force on a body will always impact objects speed?

1 answer:

Pepsi [2]3 years ago

8 0

True

Unbalanced forces are not equal, and they always cause the motion of an object to change the speed and/or direction that it is moving. When two unbalanced forces are exerted in opposite directions, their combined force is equal to the difference between the two forces.

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Factor completely x^3 + 1/8

maksim [4K]

Answer:

((2 x + 1) (4 x^2 - 2 x + 1))/8

Step-by-step explanation:

Factor the following:

x^3 + 1/8

Put each term in x^3 + 1/8 over the common denominator 8: x^3 + 1/8 = (8 x^3)/8 + 1/8:

(8 x^3)/8 + 1/8

(8 x^3)/8 + 1/8 = (8 x^3 + 1)/8:

(8 x^3 + 1)/8

8 x^3 + 1 = (2 x)^3 + 1^3:

((2 x)^3 + 1^3)/8

Factor the sum of two cubes. (2 x)^3 + 1^3 = (2 x + 1) ((2 x)^2 - 2 x + 1^2):

((2 x + 1) ((2 x)^2 - 2 x + 1^2))/8

1^2 = 1:

((2 x + 1) ((2 x)^2 - 2 x + 1))/8

Multiply each exponent in 2 x by 2:

((2 x + 1) (2^2 x^2 - 2 x + 1))/8

2^2 = 4:

Answer: ((2 x + 1) (4 x^2 - 2 x + 1))/8

5 0

3 years ago

Read 2 more answers

8p + 2 + 10 + 3p = 67

OLga [1]

Answer:

I'm guessing the answer you are wanting is false

5 0

3 years ago

Bob has some 10 ltb weights and some 3 lb weights. Together, all his weights add up to 50 lbs. If x represents the number of 3 l

____ [38]

total weight = 50

3x + 10y = 50

7 0

3 years ago

Hii can i pls have help, i will give brainliest:D

tankabanditka [31]

Answer:

4

Step-by-step explanation:

half gallon is 64 oz. 256 ÷ 64 is 4

7 0

3 years ago

Read 2 more answers

it is given that the x intercept and y intercept of a straight line L are 3 and 5 respectively. If L passes through P(k, 10) fin

statuscvo [17]

Answer:

<em>k=-3</em>

Step-by-step explanation:

<u>Equation of a line</u>

The general equation of a line can be written as:

Ax+By=C

The x-intercept is the point where the line crosses the x-axis, i.e. y=0, thus replacing x=3 and y=0:

A(3)+B(0)=C

3A=C

Solving for A:

A=C/3

The y-intercept is the point where the line crosses the y-axis, i.e. x=0, thus replacing x=0 and y=5:

A(0)+B(5)=C

5B=C

Solving for B:

B=C/5

Replacing into the general equation:

$\displaystyle \frac{C}{3}x+\frac{C}{5}y=C$

Simplifying by C:

$\displaystyle \frac{x}{3}+\frac{y}{5}=1$

The point P(k,10) belongs to the line, thus:

$\displaystyle \frac{k}{3}+\frac{10}{5}=1$

Operating:

$\displaystyle \frac{k}{3}+2=1$

$\displaystyle \frac{k}{3}=-1$

Multiplying by 3:

$\boxed{k=-3}$

7 0

3 years ago