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3 years ago

What is the Improper Fraction for this number??? 1 3/4

Mathematics

2 answers:

ohaa [14]3 years ago

7 0

Answer:

7/4

Step-by-step explanation:

murzikaleks [220]3 years ago

6 0

Multiply 1x4 then add 3, so 7/4

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The graph shows the profit per month for the 10 months during which Swanson's Restaurant has been open. Which is a valid predict

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Answer:

about $4,000 - $6,000

Step-by-step explanation:

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3 years ago

Graph the equation (x - 3)^2 + (y - 2)^2 = 25 and y = 6.

Dmitriy789 [7]

Answer:

x=6, x=0

Step-by-step explanation:

$(x - 3) ^{2}$ + $(y - 2) ^{2}$ = 25

$(x - 3) ^{2}$ + $(6 - 2) ^{2}$ = 25

x=6, x=0

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3 years ago

The graph shows Marcia's walk. Which statement best describes what Marcia could be doing on the interval from B to C? A. Marcia

vodomira [7]

Answer:

B. Maria is walking home

Step-by-step explanation:

Sana nakatulong

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3 years ago

Read 2 more answers

Suppose a population grows according to the logistic equation but is subject to a constant total harvest rate of H. If N(t) is t

Elenna [48]

Answer:

a) Equilibrium point : [ 947, 53 ]

b) N = 947 is stable equilibrium, N = 53 is unstable equilibrium

c) N0, the population will not go extinct

Step-by-step explanation:

Given that;

r = 2, k = 1000, H = 100

dN/dT = R(1 - N/k)N - H

so we substitute

dN/dt = 2( 1 - N/1000)N - 100

now for equilibrium solution, dN/dt = 0

2( 1 - N/1000)N - 100 = 0

((1000 - N)/1000)N = 50

N^2 - 1000N + 50000 = 0

N = 1000 ± √(-1000)² - 4(1)(50000)) / 2(1)

N = 947.213 OR 52.786

approximately

N = 947 OR 53

Therefore Equilibrium point : [ 947, 53 ]

g(N) = 2( 1 - N/1000)N - 100

= 2N - N²/500 - 100

g'(N) = 2 - N/250

SO AT 947

g'(N) = g'(947) = 2 - 947/250 = -1.788 which is less than (<) 0

so N = 947 is stable equilibrium

now AT 53

g'(N) = g"(53) = 2 - 53/250 = 1.788 which is greater than (>) 0

so N = 53 is unstable equilibrium

The capacity k=1000

If the population is less than 53 then the population will become extinct but since the capacity is equal to 1000 then the population will not go extinct.

6 0

3 years ago

Given the inequality: m − 11 ≤ 16 or 15 − 2m < −7 Solve for j and graph the solution on a number line. Must show your work to

Olenka [21]

Answer:

m ≤ 27 or m > 11

m is all real number since we have the or

Step-by-step explanation:

m − 11 ≤ 16 or 15 − 2m < −7

Lets solve the one on the left first

m − 11 ≤ 16

Add 11 to each side

m-11+11 ≤ 16 +11

m ≤ 27

Now lets solve the one on the right

15 − 2m < −7

Subtract 15 from each side

15 −15- 2m < −7 -15

-2m < -22

Divide by -2, remembering to flip the inequality

-2m/-2 > -22/-2

m > 11

8 0

3 years ago