Answer:
4.95+0.10x=120
Step-by-step explanation:
Hope this helps
Answer:
No its 2 so the red one...........
Answer:
The product of the Width and Length is x^2 + 4x + 3 cm^2.
Step-by-step explanation:
The volume of a box = 5x^3 + 20x^2 + 15x cm^3.
Volume of a Box = W*L*H [Width(W), Length(L), and Height(H)]
W*L*(5x) = 5x^3 + 20x^2 + 15x cm^3
W*L = (5x^3 + 20x^2 + 15x cm^3)/5x cm
W*L = x^2 + 4x + 3 cm^2
We know the area of the base of the box (W*L). It is x^2 + 4x + 3 cm^2.
To find the actual width and length, we need to know one of the variables, L or W. Without that, all we can say is that their product (W*L) is x^2 + 4x + 3 cm^2.
When we substitute a specific valuefor each variable, and then perform the operations, it's called evaluating theexpression. Let's evaluate theexpression 3y + 2y when 5 = y. Click on the steps to see how it's done. Perform the operations, to find the value of the expression.
Answer:
(x - 6)² + (y - 2)² = 128
Step-by-step explanation:
Given as the circle has center ( 6 , 2)
and it passes through points (-2 , -6)
Now , standard equation of circle is (x -a)² + (y- b)² = r² , where (a , b) is center and r is the radius .
Again from given center the circle equation is
(x- 6)² + (y- 2)² = r²
Now this circle passes through points (-2 , -6)
so, (-2 -6)² + (-6 -2)² = r²
so, 8² + 8² = r²
Or, 128 = r²
i.e Radius pf this circle = 8
Hence the circle equation formed is
(x- 6)² +( y-2)² = 128 Answer
