(2^4)^2 x 2^0
(2^4)=2x2x2x2=16
16^2=16x16=256
2^0=1
256x1=256
Hope this helps
A line....because it is a border line
Answer:
A=$643.15
Step-by-step explanation:
We can use the formula
![A=P(1+\frac{r}{n} )^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bnt%7D)
Now we can plug the information in the problem into the formula
![A=540(1+\frac{0.06}{1} )^{(1)(3)}\\\\A=643.15](https://tex.z-dn.net/?f=A%3D540%281%2B%5Cfrac%7B0.06%7D%7B1%7D%20%29%5E%7B%281%29%283%29%7D%5C%5C%5C%5CA%3D643.15)
Answer:
approximately 300,000,000 meters per second
Answer:
80 members
Step-by-step explanation:
Let the band members be= b and the chorale members= c
Then, according to question, b=c+30 and ![\frac{b+10}{c+10}=\frac{3}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bb%2B10%7D%7Bc%2B10%7D%3D%5Cfrac%7B3%7D%7B2%7D)
⇒![2(b+10)=3(c+10)](https://tex.z-dn.net/?f=2%28b%2B10%29%3D3%28c%2B10%29)
⇒![2b+20=3c+30](https://tex.z-dn.net/?f=2b%2B20%3D3c%2B30)
⇒![2b-3c=30-20](https://tex.z-dn.net/?f=2b-3c%3D30-20)
⇒![2b-3c=10](https://tex.z-dn.net/?f=2b-3c%3D10)
Now, substituting the value of b=c+30, we get
⇒![2(c+30)-3c=10](https://tex.z-dn.net/?f=2%28c%2B30%29-3c%3D10)
⇒![2c+60-3c=10](https://tex.z-dn.net/?f=2c%2B60-3c%3D10)
⇒![-c=-50](https://tex.z-dn.net/?f=-c%3D-50)
⇒![c=50](https://tex.z-dn.net/?f=c%3D50)
Therefore, ![b=c+30](https://tex.z-dn.net/?f=b%3Dc%2B30)
![b=50+30=80](https://tex.z-dn.net/?f=b%3D50%2B30%3D80)
Therefore, there are 80 members in the band.