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avanturin [10]
3 years ago
6

The student council sold jars of mixed nuts at their bazaar they were given 40 empty jars. They paid $19.60 for the nuts and $11

.20 for decorative ribbon they made a profit of 98¢on each of the 40 jars sold. How much did they charge for each jar
Mathematics
1 answer:
Alex Ar [27]3 years ago
3 0

Answer:

\$1.75

Step-by-step explanation:

Total amount paid for the nuts is $19.60

Total amount paid for the ribbons is $11.20

Profit made on each jar is 98¢= $0.98

Cost price of the nuts and ribbon for the 40 jars is 19.6+11.2=\$30.8

Cost price for nuts and ribbonn for one jar = \dfrac{30.8}{40}=\$0.77

Selling price is the sum of the cost price and profit.

Selling price for one jar = 0.77+0.98=\$1.75

They charged \$1.75 for each jar.

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A rectangular garden measures 29 ft by 37 ft. surrounding (and bordering) the garden is a path 2 ft wide . find the area of this
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Answer: The area of the path is 280 ft^2

(Note that 280 ft^2 means “280 feet squared”)

Step-by-step explanation: The first clue in this question is the dimensions of the rectangular garden which have been given as 29 ft by 37 ft. So we can conveniently compute the area of the garden as follows;

Area = L x W

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Area = 37 x 29

Area = 1037 ft^2

However there is a path surrounding the garden which is 2 ft wide on all four sides. This means both borders of the length have an extra 4 feet of measurement while both borders of the width also have an extra 4 feet of measurement. So, if the surrounding border and garden is measured altogether, the length would become (37 + 4= 41) 41 feet while the width would become (29 + 4 = 33) 33 feet. So the area of the garden and the surrounding path inclusive can be calculated as

Area = L x W

Area = 41 x 33

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To determine the area of ONLY THE SURROUNDING PATH, we simply deduct the area of the GARDEN ONLY (1073 ft^2) from the area of GARDEN AND SURROUNDING PATH (1353 ft^2)

Therefore area of the path surrounding the garden becomes

Area of path = 1353 - 1073

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