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irina [24]
3 years ago
15

What is the solution to the equation log2 (5x - 2) = 3?

Mathematics
1 answer:
Advocard [28]3 years ago
4 0

From log BNE to BEN

X=2

if you want explaination then ask me

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d= -5

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What is the change in elevation from -6 km to -14 km?
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-8 km

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I need to know the answer and how to solve this
AURORKA [14]

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135

Step-by-step explanation:

subtract 180 by 45 since a line is 180, that is what you get for the angle that is adjacent to angle 2, there is a rule if it is adjacent, they equal each other. thus, angle 2 is 135

5 0
2 years ago
Math problem help me. I got it wrong I think
lukranit [14]

Answer:

The answer is B

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I got y=-4x+7

So they give us the slope which is negative 4

so you would throw in the x coordinate with the slope and multiply to get y=-12+7

then you would use the y coordinate to substitute the Y

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i add twelve on both sides and end up with the y intercept being 7]

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8 0
2 years ago
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
2 years ago
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