All categories

3 years ago

If a movie starts at 7:00 and runs for a 108 minutes what time does it end

Mathematics

1 answer:

zepelin [54]3 years ago

4 0

108 minutes gives us 1 hour and 48 minutes.
Adding this to the starting times gives us the answer
i.e 8.48 am/pm

You might be interested in

Under her cell phone plan, Nevaeh pays a flat cost of $46.50 per month and $5 per gigabyte, or part of a gigabyte. (For example,

Akimi4 [234]

Answer:

She can only use one gigabite.

Step-by-step explanation:

8 0

3 years ago

Write an equation that you could use to calculate the distance from NIGEL's feet to the balloon. Let x represent the unknown dis

Sholpan [36]

X2+122=182 I think sorry if am not right

7 0

3 years ago

Read 2 more answers

A new aircraft control system is being designed that must be 98.0% reliable. This system consists of two components in series.

sweet [91]

Answer:

98.99%

Step-by-step explanation:

The combined reliability of both components must be 98%. Given that both components must be functional and have the same reliability 'r', the minimum value of 'r' that meets the system requirements is given by:

$0.98 = r^2\\r=0.9899=98.99\%$

The level of reliability required for each component is 98.99%.

6 0

3 years ago

Rilet rode his bike for 360 minutes if he traveled 2 miles per hour how many miles did he travel

Tanzania [10]

Rilet drove 12 miles.

6 0

3 years ago

The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth g

Bingel [31]

Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.

Answer:

"The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

Step-by-step explanation:

This is a problem of the distribution of sample means. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves normally for samples sizes equal or greater than 30 $\\ n \geq 30$ . Mathematically

$\\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$ [1]

In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.

Moreover, we know that the variable Z follows a normal standard distribution, i.e., a normal distribution that has a population mean $\\ \mu = 0$ and a population standard deviation $\\ \sigma = 1$ .

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [2]

From the question, we know that

The population mean is $\\ \mu = 88$ WPM
The population standard deviation is $\\ \sigma = 14$ WPM

We also know the size of the sample for this case: $\\ n = 137$ sixth graders.

We need to estimate the probability that a sample mean being greater than $\\ \overline{X} = 89.87$ WPM in the distribution of sample means. We can use the formula [2] to find this question.

The probability that the sample mean would be greater than 89.87 WPM

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}$

$\\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}$

$\\ Z = 1.5634 \approx 1.56$

This is a standardized value and it tells us that the sample with mean 89.87 is 1.56 standard deviations above the mean of the sampling distribution.

We can consult the probability of P(z<1.56) in any cumulative standard normal table available in Statistics books or on the Internet. Of course, this probability is the same that $\\ P(\overline{X} < 89.87)$ . Then

$\\ P(z$

However, we are looking for P(z>1.56), which is the complement probability of the previous probability. Therefore

$\\ P(z>1.56) = 1 - P(z$

$\\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594$

Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

5 0

3 years ago