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ahrayia [7]
3 years ago
13

Everyday Jo practices her tennis serve by continually serving until she has had a total of 50 successful serves.

Mathematics
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

To reach her goal in the first 100 serves she has to have 50 successful services. This happens with a probability of 2%.

That means she has 98% chances of needing more than 100 serves to reach her goal.

Step-by-step explanation:

The condition for Jo to need more than 100 serves is that she do not accomplish 50 successful serves in 100 tries.

We have a probability sample of possible results that hass a binomial distribution, with n=100 and p=0.4.

As n is large enough, we will approximate it with a normal distribution. The parameters of the normal distribution are:

\mu=np=100\cdot0.4=40\\\\\sigma=\sqrt{np(1-p)}=\sqrt{100\cdot0.4\cdot0.6}=\sqrt{24}=4.9

We need the to calculate the probability that the amount of successful services is less than 50, so that she needs more than 100 serves. This is:

P(X

We calculate the z value for X:

z=(X-\mu)/\sigma=(50-40)/4.9=2.04

Then we have

P(X

That means that there is 98% probability that she will need more than 100 serves to reach her goal.

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Find the slope (12,2),(18,-2)
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Answer:

\frac{-2}{3}

Step-by-step explanation:

y2-y1/x2-x1

-2-2/18-12

-4/6

-2/3

3 0
3 years ago
Does the 4 in 4,567 have the same value as the 4 in 34,811
IRISSAK [1]

Answer:

Yes it does because 4,567 is just like 34,811 you just add the 3 to the first one an then look at the thousands place an it is the sam look

..4,567

34,811

where the . are you just add a number for say like 3 an than it is the same

Hope it helps:)

4 0
3 years ago
Read 2 more answers
There is a triangle the angles are 2x 3x and x how do you get the answer
Marta_Voda [28]
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I hope
7 0
3 years ago
Whats 3,684,266 to the nearest hundred thousand and million
grin007 [14]
The nearest hundred thousand is 3,700,000
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4 0
4 years ago
Someone ask me to solve this.
Semenov [28]
X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 ----->  3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

 3k +4h =4          ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4  or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4  , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3 

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .




6 0
3 years ago
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