Find the distance between Point A(9, 10) and B(-1,9) to the nearest tenth.
1 answer:
Answer:
10.0
Step-by-step explanation:
see attached for reference.
given two points in the x-y axis (x₁, y₁) and (x₂, y₂)
the distance bettween them is given by
Distance, D = √ ( (x₂-x₁)² + (y₂-y₁)² )
In our case we are given points (9,10) and (-1,9)
substituting these into the formula , we get:
D = √ ( (9-10)² + (-1-9)² )
= √ ( (-1)² + (-10)² )
= √ ( 1 + 100 )
=√101
= 10.04988
= 10.0 (rounded to nearest tenth)
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