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2 years ago

Can some help ...:.....0

Mathematics

1 answer:

frozen [14]2 years ago

7 0

Answer:

-4

Step-by-step explanation:

Two legs of the triangle are congruent as shown by the tick marks. This means that this is an isosceles triangle; in an isosceles triangle, the two base angles are also congruent. Which means <A and <B are congruent.

So to solve for x, set 28 and 10x+68 equal to each other.

28=10x+68

First, subtract 68 from both sides

-40=10x

Then, divide both sides by 10

-4=x

If you want to check your answer plug -4 back into the original equation.

28=10(-4)+68

28=-40+68

28=28, which is true, therefore -4 is correct.

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Yakvenalex [24]

Answer:

Are you cheating?

Step-by-step explanation:

5 0

3 years ago

REAL LIFE A cylindrical hazardous waste container has a diameter of 1.5 feet and a height of 1.6 feet. Abo

aivan3 [116]

Answer:

It can hold up to $1.256ft^3$ of waste

Step-by-step explanation:

Given

$D = 1.5ft$ -- Diameter

$h = 1.6ft$ -- height

Required

Determine the amount of waste it can hold

This simply means that we calculate the volume of the cylindrical container.

And this is calculated using:

$Volume = \pi r^2h$

Where

$\pi = 3.14$

and

$r = \frac{D}{2}$

$r = \frac{1.5}{2}$

$r = 0.75$

So, we have:

$Volume = 3.14 * 0.5^2 * 1.6$

$Volume = 1.256ft^3$

Hence, it can hold up to $1.256ft^3$ of waste

3 0

3 years ago

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.