Solve for x over the real numbers:
5 x^2 - 21 = 10 x
Subtract 10 x from both sides:
5 x^2 - 10 x - 21 = 0
Divide both sides by 5:
x^2 - 2 x - 21/5 = 0
Add 21/5 to both sides:
x^2 - 2 x = 21/5
Add 1 to both sides:
x^2 - 2 x + 1 = 26/5
Write the left hand side as a square:
(x - 1)^2 = 26/5
Take the square root of both sides:
x - 1 = sqrt(26/5) or x - 1 = -sqrt(26/5)
Add 1 to both sides:
x = 1 + sqrt(26/5) or x - 1 = -sqrt(26/5)
Add 1 to both sides:
Answer: x = 1 + sqrt(26/5) or x = 1 - sqrt(26/5)
D. 41x + 11y
You add the like terms so the 23 and 18 to equal 41
Answer: I think it is B
Step-by-step explanation:
Answer:
multiply can u make me the brainliest
Step-by-step explanation:
Answer:
Using the quadratic formula to solve 5x = 6x^2 – 3, what are the values of x?
5x = 6x^2 – 3
Subtract 5x from both sides:
0 = 6x^2 – 5x – 3
a = 6, b = -5, c = -3
x = (-b ± √(b^2 - 4ac))/(2a)
x = (-(-5) ± √((-5)^2 - 4(6)(-3)))/(2(6))
x = (5 ± √(25 + 72))/12
x = (5 ± √(97))/12
Step-by-step explanation:
