Answer:
Let M represents the Male and F represents the Female.
As per the statement:
There are 6 times as many males as females on the maths course at university.
⇒ M = 6F
Total number of person on the maths course = M + F = 6F+ F = 7F
we have to find the fraction of the course are male;
Substitute the given values we have;
therefore, the fraction of the course are male is, 
Answer:
5000
Step-by-step explanation:
i worked the problem out and got 100%
Answer:
x = 24.99 or 25
Step-by-step explanation:
<em>Using sin to figure out the angle of ABD, we can figure out the angle of CBD by subtracting it from 90°.</em>
sin y = (1/5)
y = 11.54°
90 - 11.54 = 78.46°
<em>Now using Pythagorean Theorem (</em><em>a²+b²=c²</em><em>) we can solve for line BD.</em>
1² + b² = 5²
1 + b² = 25
b² = 24
b = √24
<em>Now we can use tan to figure out the length of segment DC.</em>
tan(78.46) = z/√24
z = 23.99
<em>We can now combine the known length of segment AD and the length of DC to get </em><em>x</em><em>.</em>
1 + 23.99 = 24.99 or <u>about</u> 25.
Answer:
Step-by-step explanation:
when solving and equation with a variable, you must work backwards and do the opposite of the equation
sooo… you must subtract 4 (opposite of +4 is -4)
x=12
Answer:
32.008
Step-by-step explanation:
