What is the range of the function f(x) = -2(64) + 3? 0 (-♾-2] 0 (-0,3) (-2,♾) (3.♾)

Sierra is selling bracelets to raise money for the Language Club at school. Each bracelet with yellow beads sells for $5. Each b

matrenka [14]

Answer:

Correct answer is:

$5y+6r=660\\y=2r+8$

Step-by-step explanation:

Given that Number of bracelets with yellow beads is represented by $y$

Each bracelet with yellow beads is sold for $5.

Total money raised by bracelets with yellow beads = Number of bracelets sold $\times$ Money raised by sale of one such bracelet = $5y$

Also Given that Number of bracelets with Orange beads is represented by $r$

Each bracelet with orange beads is sold for $6.

Total money raised by bracelets with orange beads = Number of bracelets sold $\times$ Money raised by sale of one such bracelet = $6r$

Given that total money raised by sale of both type of bracelets is $660.

so, the first equation becomes:

$5y+6r=660 ....... (1)$

It is also given that "The number of bracelets with yellow beads that Sierra sold is 8 more than twice the number of bracelets with orange beads"

$\Rightarrow r =2r+8 ...... (2)$

So, by equation (1) and (2), the system of equations is:

$5y+6r=660\\y=2r+8$

5 0

3 years ago

Suppose that, in the past, 40% of all adults favored capital punishment. Do we have reason to believe that the proportion of adu

Alex_Xolod [135]

Answer:

The p-value of the test is 0.1469 > 0.05, which means that there is no reason to believe that the proportion of adults favoring capital punishment today has increased, using a 0.05 level of significance.

Step-by-step explanation:

Suppose that, in the past, 40% of all adults favored capital punishment. Test if the proportion has increased:

At the null hypothesis, we test if the proportion is still of 40%, that is:

$H_0: p = 0.4$

At the alternative hypothesis, we test if the proportion has increased, that is, is greater than 40%, so:

$H_1: p > 0.4$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that $\mu = 0.4, \sigma = \sqrt{0.4*0.6}$

Random sample of 15 adults, 8 favor capital punishment.

This means that $n = 15, X = \frac{8}{15} = 0.5333$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.5333 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{15}}}$

$z = 1.05$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion of 0.5333 or more, which is 1 subtracted by the p-value of z = 1.05.

Looking at the z-table, z = 1.05 has a p-value of 0.8531.

1 - 0.8531 = 0.1469.

The p-value of the test is 0.1469 > 0.05, which means that there is no reason to believe that the proportion of adults favoring capital punishment today has increased, using a 0.05 level of significance.

3 0

2 years ago

Choose which function is represented by the graph

Viefleur [7K]

Given:

The graph of a function.

To find:

The function.

Solution:

From the given graph, it is clear that the graph intersect the x-axis at x=-4, -2, 1. It means -4, -2 and 1 are zeros of the given function graph.

If c is a zero of a function f(x), then (x-c) is a factor of f(x).

Using the above definition, we conclude that (x+4), (x+2) and (x-1) are the factors of given function. So,

$f(x)=(x+4)(x+2)(x-1)$

$f(x)=(x-1)(x+2)(x+4)$

Therefore, the correct option is A.

4 0

3 years ago

Is the bisector of ∠ABC and is the bisector of ∠ACB.

ycow [4]

Answer:

ASA

Step-by-step explanation:

You can show the angles at either end of segment BC in triangles MBC and LCB are congruent, so you have two angles and the segment between. The appropriate theorem in such a case is ASA.

7 0

3 years ago

For the equation, complete the solution. 7x + y = −18

Alex777 [14]

Answer:

x= - 18/7 - 1/7y, y

or if you are solving for y= -18-7x, x

( SEE OTHER IMAGE)

Step-by-step explanation:

See image below:)

8 0

3 years ago

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