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Rainbow [258]
3 years ago
14

PLEASE ANSWER ASAP !!!!!!!!!!!!!!!!!!! WILL GET BRAINLEST IF CORRECT!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

Answer:

B or  C or maybe A

Step-by-step explanation:

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Which algebraic expression has a term with a coefficient of 3? A -5y-7 B 3y+1 c 3(y-6) D-2y+5+3
kiruha [24]

B. 3y+1

Hope this helps! :)

7 0
3 years ago
A used car has a value of 15,250 when it’s purchased in 2012. The value of the car decreases at a rate of 7.5% per year
kotegsom [21]

p=15250

r=7.5/100=0.075

y = 15250*(1 - 0.075)^x

after 8 years it would be

x = 8

y = 15250*(1 - 0.075)^8

y = $8,173.42

after 8 years the value of the car is going to be $8,173.42

8 0
3 years ago
Two pools are leaking After 15 minutes pool A has leaked 2/3 gallon After 20 minutes pool B has 3/4 gallon Which pool is leaking
Nataly [62]

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8 0
3 years ago
90 is 25% of what number
AysviL [449]
360 is the answer because 90 times 4 is equal to 360
5 0
3 years ago
A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading
Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

b.

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0
3 years ago
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