Hi there!


We can evaluate using the power rule and trig rules:



Therefore:
![\int\limits^{12}_{2} {x-sin(x)} \, dx = [\frac{1}{2}x^{2}+cos(x)]_{2}^{12}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B12%7D_%7B2%7D%20%7Bx-sin%28x%29%7D%20%5C%2C%20dx%20%3D%20%5B%5Cfrac%7B1%7D%7B2%7Dx%5E%7B2%7D%2Bcos%28x%29%5D_%7B2%7D%5E%7B12%7D)
Evaluate:

3 times 24 is 48% therefore its D.
The radius of the circle is 1.
Answer:
60 feet
Step-by-step explanation:
The height, h (in meters), of the object launched from a platform is represented by the equation

where x is the time (in seconds) passed after the launch.
The time of launch is
(0 seconds passed after the launch)
Substitute
to find the height:

Answer:
2=4x+7
Step-by-step explanation: