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2 years ago

After the priest ruled the city who became the 1st king of the city ?

Mathematics

2 answers:

Mashutka [201]2 years ago

8 0

Answer:

Uruk

Step-by-step explanation:

The legendary king Gilgamesh, according to the chronology presented in the ... In addition to being one of the first cities, Uruk was the main force of ... the Eridu period when it was one of the oldest and most important cities of Sumer.

cricket20 [7]2 years ago

6 0

Answer:

son of the priest

Step-by-step explanation:

I guess

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Which number line represents the solution of 4x - 9 > - 21?

Aleks04 [339]

Answer:4x -9 >= -21

4x >= -12

x >= -12/4

x >= -3

so this number line started with -3 and go away till + infinity

hope this will help you

3 0

2 years ago

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IRISSAK [1]

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2 years ago

Brayden, Howard, and Vincent are on the football team. During a game, Brayden gains 1 less than 5 times the average number of ya

Gnoma [55]

Answer: If two pair is parallel then it has no solution.

Step-by-step explanation:

Since we have given that

Let the number of gained yards by each player be y

For the case of Brayden:

Equation will be

$y=5x-1\\\\y-5x=-1$

For the case of Howard :

Equation will be

$y=5x+1\\\\y-5x=1$

For the case of Vincent :

$y=4x+5\\\\y-4x=5$

Since First two equations are parallel so it has no solution.

Reason:

$y-5x=1\\\\y-5x=-1\\\\\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\\\\\frac{1}{1}=\frac{5}{5}\neq \frac{1}{-1}$

Hence, if two pair is parallel then it has no solution.

8 0

2 years ago

Read 2 more answers

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

<u>Right part:</u>

$\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Since simplified left and right parts are the same, then the equality is true.

3 0

2 years ago

Pls help me with 4 , 5 , and 6 and show me how you did it i will mark brainlist !!

LuckyWell [14K]

Answer:

2 on top and bottom of 4 5 is 3 on top and bottom and lastly 6 is 8 on top and bottom.

Step-by-step explanation:

all you have to do is divide the two bottom numbers on each problem and the answer to the problem will be the same on top and bottom

3 0

3 years ago

After the priest ruled the city who became the 1st king of the city ? ​

After the priest ruled the city who became the 1st king of the city ?