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Inga [223]
3 years ago
7

Which technique combines two-dimensional Images Into a three-dimensional Image?

Advanced Placement (AP)
2 answers:
Len [333]3 years ago
8 0

Answer:

stereoscopic

Explanation:

PLATO

erica [24]3 years ago
6 0

Answer:

Originally, stereogram referred to a pair of stereo images that could be viewed using a stereoscope. Most stereoscopic methods present two offset images separately to the left and right eye of the viewer. These two-dimensional images are then combined in the brain to give the perception of 3D depth.

Explanation:

The stereoscopic  technique combines two-dimensional images and enhances them to create a three-dimensional image. This technique is used by forensic scientists to recreate crime scenes and evidence.

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Use the data in the chart to answer the question.
puteri [66]

The mode for this set of data is: 45.

<h3>What is mode?</h3>

Mode can be defined as the number that appear more than other numbers.

The given chart is:

Anxious behaviors per hour

Subject 1 60

Subject 2 45

Subject 3 20

Subject 4 70

Subject 5 45

Based on the above chart we can see 45 in subject 2 and 45 in subject 5 which in turn means  that 45  appear more than others numbers as it appear twice.

Therefore The mode for this set of data is: 45.

Learn more about mode here:brainly.com/question/14532771

#SPJ1

3 0
1 year ago
If someone has a current gpa of 4.33, what does that mean? Do they have a good change to go to a competitive school? (Just based
elena-s [515]
Yes it actually does because in most schools you have to have a gpa of 4.0
8 0
3 years ago
Read 2 more answers
I can’t figure this problem out
Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

\int\limits^4_1 {(3f(x)+2)} \, dx

So lets break this up into two different integrals that represent the same area.

\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

\int\limits^4_1 {f(x)} \, dx

But since we have these values we can say that:

-3 - 2 = -5

Which means that \int\limits^4_1 {f(x)} \, dx = -5

So now we can evaluate \int\limits^4_1 {(3f(x)+2)} \, dx

Lets first break up our integrand into two integrals

\int\limits^4_1 {(3f(x)+2)} \, dx = 3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx

Now we can evaluate this:

We know that \int\limits^4_1 {f(x)} \, dx = -5

So:

3(-5)+2[x] where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

5 0
3 years ago
ADVICE: I have a class in which there are 5 teachers and 15 students, and for the past 3 days I've been trying to receive help a
nlexa [21]

Answer:

that should mean 3 students per teacher. i would reccomend sending an email or having a conference on the attention given to you something like that

Explanation:

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If someone has been sentenced to a structured living environment such as a halfway house, then that person is
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B...............I think ...........................
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