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emmasim [6.3K]
3 years ago
8

What is the value of x? NO LINKS IF YOU DO I AM REPORTING

Mathematics
1 answer:
kari74 [83]3 years ago
3 0

Answer: -6

Step-by-step explanation: i had this too

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Roger walked to 1/2 kilometer from his home to the park. Then he walked 200 meters in the park, and walked home. How far did he
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HELLO

Rodger my good friend walked 1200 meters.

Kilo- 1000m

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Which of the following equations is equivalent to x - y = 6?
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I believe the answer would be A. 2x-y=6 :)
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Please help me, I don't know how to do this...
Lunna [17]

Answer:

  A.  5

Step-by-step explanation:

The triangle will be a right triangle when the side lengths satisfy the Pythagorean theorem: the sum of the squares of the legs is equal to the square of the hypotenuse.

  (x +1)^2 +x^2 = (√61)^2

  x^2 +2x +1 +x^2 = 61 . . . eliminate parentheses

  2x^2 +2x = 60 . . . . . . .subtract 1, collect terms

  x^2 +x -30 = 0 . . . . . divide by 2, subtract 30

  (x +6)(x -5) = 0 . . . . factor the quadratic

  x = -6 or +5

The solution is x = 5.

_____

Side lengths cannot be negative. Solution values are values of x that make the factors zero. x+6=0 when x=-6, for example.

8 0
2 years ago
3. The student council bought t-shirts from a company for $9 apiece. They also spent a
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3 years ago
A cryptographic hash takes a message as input and produces a fixed-length string as output, called the digital fingerprint. A br
Allushta [10]

Answer:

1.85x10^{19} attempts are required to find a matching pair if the digital fingerprint is 64 bits long.

3.40*10^{38} attempts are required to find a matching pair if the digital fingerprint is 128 bits long.

Step-by-step explanation:

Each bit has two options. So

How many attempts are required to find a matching pair if the digital fingerprint is 64 bits long?

So for each of the 64 bits, we have the following number of options.

2 - 2 - 2 - 2 -... - 2

So, in all, there are

T = 2^{64} = 1.85x10^{19}

options.

So, 1.85x10^{19} attempts are required to find a matching pair if the digital fingerprint is 64 bits long.

128 bits long?

Using the same logic as the first question.

T = 2^{128} = 3.40*10^{38}

So, 3.40*10^{38} attempts are required to find a matching pair if the digital fingerprint is 128 bits long.

5 0
3 years ago
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