The answer is true. Hope this helps. Mark brainest
Answer:
it would be the Adjacent side (8) over the Hypotenuse, or the longest side which is 10. an easy way to remember this is CAH or Cosine=Adjacent/Hypotenuse
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)
Answer:
area = 12 m²
Step-by-step explanation:
area = L x W
area = 4 x 3 = 12 m²
1. Use Difference of squares: a^2-b^2=(a+b)(a-b)
(x+k)(x-k)=0
2. Solve for x and k
x=+-k
k=+-x