Answer:
y" = csc(x)[9cot²(x) - csc²(x)]
Step-by-step explanation:
Step 1: Define
y = 9csc(x)
Step 2: Find 1st derivative
y' = -9csc(x)cot(x)
Step 3: Find 2nd derivative
y" = 9csc(x)cot(x)cot(x) + -csc(x)csc²(x)
y" = 9csc(x)cot²(x) - csc³(x)
y" = csc(x)[9cot²(x) - csc²(x)]
Answer:
excusme where is the model
Step-by-step explanation:
8x+8y=2
-) 8x+5y=1
——————
3y=1
y=1/3
8x+8(1/3)=2
24x+8=6
24x=-2
x=-1/12
(-1/12,1/3)
The 25th percentile corresponds to z ≈ -0.67.
The 90th percentile corresponds to z ≈ 1.28.
So, you can write two equations in μ and σ as here:
.. μ -0.67σ = 10
.. μ +1.28σ = 20
The solution is
.. μ ≈ 13.45
.. σ ≈ 5.11
3(-1)-7= -10
3(0)-7= -7
3(1)-7= -4
3(2)-7= -1
3(3)-7= 2
therefore range = {-10,-7,-4,-1,2}