Caroline has a unique pet chimpanzee that is relatively likely to have twins. Each pregnancy is independent, and Caroline's chim
panzee has a 60% chance of having 1 baby and a 40% chance of having 2 babies each pregnancy
If X is a random variable that represents the total number of chimpanzee babies if Caroline's chimpanzee gets
pregnant twice, drag the bars to graph the probability distribution for all possible values of X.
We can solve this by setting up a proportion where 864/12 = 504/x. We cross multiply and get 864x = 504 * 12. So 864x = 6048. Divide by 864 on both sides, x = 7.