Point T is the midpoint of J and H.
x-coordinate is 0 for the three points.
y-coordinate of T is in the middle of the y-coordinate of J and the y-coordinate of H. So, y-coordinate of H has to be 6, because (6+2)/2=8/2=4.
Then point H is (0,6).
1) 2.92• 10^-3 2) 2.16•10^7. 3)7.5•10^8
we know that
If the only factors a polynomial are
and itself, then that polynomial is prime.
so
If the polynomial has at least one root (one x-intercept) then the polynomial is not prime
Using a graph tool
<u>case 1) </u>

see the attached figure N 1
The polynomial has one root-------> the polynomial is not prime
<u>case 2) </u>

see the attached figure N 2
The polynomial has three roots-------> the polynomial is not prime
<u>case 3) </u>


see the attached figure N 3
The polynomial has zero roots-------> the polynomial is prime
<u>case 4)</u>


see the attached figure N 4
The polynomial has two roots-------> the polynomial is not prime
therefore
<u>the answer is</u>
------> is prime