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ruslelena [56]
3 years ago
11

What is the proper seperation of factors for this equation ∛24n² × ∛36n²

Mathematics
1 answer:
Gwar [14]3 years ago
8 0

Answer:

{ \tt{ \sqrt[3]{24 {n}^{2}  }  \times  \sqrt[3]{36 {n}^{2} } }} \\  = { \tt{(  {n}^{ \frac{2}{3} })( \sqrt[3]{864})  }}

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Please help! Will give Brainliest!!
Valentin [98]

Answer:

$133507.33

Step-by-step explanation:

x = number of 6 month periods

y = total money in account

After 10 years:

y = 300x(1.09)^x

y = 300(20)(1.09)^2^0

y = 6000(5.60441077)

y = 33626.46

After 18 years:

y = 33626.46(1.09)^x

y = 33626.46(1.09)^1^6

y = 33626.46(3.97030588)

y = 133507.33

6 0
3 years ago
Corgurent or supplementary
nataly862011 [7]

Answer:

Congruent:

B, E, F, G

The rest are supplementary.

Step-by-step explanation:

Mark me Brainliest?

5 0
3 years ago
I NEED HELP ASAP!!!!!!
krek1111 [17]

Answer:

83.3%

Step-by-step explanation:

The probability of rolling a 3 on a 6-sided dice is 1/6

Since you don't want a three, there's a 5/6 chance of not rolling a 3

5/6 (use calculator and divede 5 by 6) = 0.833333 (move decimal 2 to the right) = 83.3%

Therefore, the most reasonable answer would be C, 83.3%

3 0
3 years ago
Candace has $20 more than Amar. Their combined money totals $95. Write a system of equations represents this situation
STALIN [3.7K]

Answer:

Candace has $57.5 and Amar has $37.5.

Step-by-step explanation:

x+(x+20)=z

x+20=y

x+y=z

--------------

2x+20=95

2x=95-20

2x=75

x=75/2

x=37.5

37.5+20=y=57.5

5 0
3 years ago
Read 2 more answers
Solve the equation to find where the treste ground levelEnter your answers from least to greatest and round to the nearest The m
DaniilM [7]

Answer:

The trestle meets ground level at 0.875 units and 9.125 units

Step-by-step explanation:

Poorly formatted question.

The given equation is:

y = -x^2 + 10x - 8

Required

The point where the trestle gets to the ground level

To do this, we set y = 0

So, we have:

-x^2 + 10x - 8 = 0

Multiply through by -1

x^2 -10x + 8 = 0

Solve using quadratic formula:

x= \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

Where:

a = 1; b =-10; c = 8

So, we have:

x= \frac{-(-10) \± \sqrt{(-10)^2 - 4*1*8}}{2*1}

x= \frac{-(-10) \± \sqrt{68}}{2*1}

x= \frac{-(-10) \± 8.25}{2}

x= \frac{10 \± 8.25}{2}

Solve the fraction

x= 5 \± 4.125

Split

x= 5 + 4.125\ or\ x= 5 - 4.125

x= 9.125\ or\ x= 0.875

7 0
3 years ago
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