which expression is equivalent to the expression shown? 3 to the power of 7 X 3 to the power os negative 4

What is (1.2 x 10^-2) x (3 x 10^5)

liraira [26]

Answer:

B. 3.6 x 10^3

Step-by-step explanation:

(1.2 x 10^-2) x (3 x 10^5)

When we multiply terms with powers , we multiply the factors out front and add the exponents

a * 10^b * c* 10^d = ac * 10^(b+d)

(1.2 x 10^-2) x (3 x 10^5) = (1.2* 3) * 10^(-2+5)

= 3.6 * 10 ^3

6 0

3 years ago

She earns $3.10 for each hour she works and $2.30 for each bushel of apples she picks. Her goal is to earn at least $100 this we

nika2105 [10]

The inequality would be 3.1h + 2.3b ≥100

Step-by-step explanation:

Earning of Tammy for each hour of work= $3.1

Total hours she worked= h

Earning for picking each bushel of apple= $2.3

Total bushel she picks= b

Her goal = minimum of $100

Hence total earning from working= earning from each hour* no of hours worked

Total earning= 3.1h

Similarly, total earning from picking up apple bushels= earning from picking one bushel*no of bushels picked

Total earning= 2.3b

According to question total earning must be greater than $100

Hence, 3.1h + 2.3b ≥100

3 0

3 years ago

What is 6:12 in simpiest form?

g100num [7]

Answer:

6:12=1:2

Step-by-step explanation:

as we will cut 6:12 by 6 . please mark me as brainliest and follow me

5 0

3 years ago

Read 2 more answers

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$