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Tems11 [23]
3 years ago
14

In a school survey, three homerooms are chosen and 10 students from each homeroom are randomly chosen to complete the survey. Id

entify the sampling method.
Mathematics
1 answer:
lesya [120]3 years ago
6 0

Answer:

This sampling method used in this question is the stratified sampling method.

Step-by-step explanation:

There are about 5 known sampling methods.

- Random Sampling

In random sampling, each member of the population has an equal chance of being surveyed. All the students are given a number and random numbers are generated to pick the students to be surveyed.

- Systematic sampling

This is easier than random sampling. In systematic sampling, a particular number, n, is counted repeatedly and each of the nth student is picked to be sampled.

- Convenience Sampling

This is the worst sampling technique. It is also the easiest. In Convenience sampling, the surveyor just surveys the first set of students that they find.

- Cluster sampling

Cluster Sampling divides the population into groups which are called clusters or blocks. The clusters are selected randomly, and every element in the selected clusters is surveyed.

- Stratified Sampling

Stratified sampling divides the population into groups called strata. A sample is taken from all or some of these strata using either random, systematic, or convenience sampling. This is evidently the answer to the question as the students are divided into homerooms (strata) and samples are now randomly taken from 3 randomly selected strata.

Hope this Helps!!!

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3 years ago
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The quadratic function in vertex form of a parabola vertex 1,1 and passes through 4,19
Grace [21]

Answer:

y = 2(x - 1)² + 1

Step-by-step explanation:

The equation of a quadratic function in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (1, 1), thus

y = a(x - 1)² + 1

To find a substitute (4, 19) into the equation

19 = a(4 - 1)² + 1

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3 years ago
In a survey of 603 adults, 98 said that they regularly lie to people conducting surveys. Create a 99% confidence interval for th
marysya [2.9K]

Answer:

The population proportion is estimated to be with 99% confidence within the interval (0.1238, 0.2012).

Step-by-step explanation:

The formula for estimating the population proportion by a confidence interval is given by:

\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}

Where:

\hat{p} is the sample's proportion of success, which in this case is the people that regularly lie during surveys,

z_{\alpha /2} is the critical value needed to find the tails of distribution related to the confidence level,

n is the sample's size.

<u>First</u> we compute the \hat{p} value:

\hat{p}=\frac{successes}{n}=\frac{98}{603}=0.1625

<u>Next</u> we find the z-score at any z-distribution table or app (in this case i've used StatKey):

z_{\alpha /2}=2.576

Now we can replace in the formula with the obtained values to compute the confidence interval:

\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}=0.1625\pm 2.576\times\sqrt{\frac{0.1625\times(1-0.1625)}{603}}=(0.1238, 0.2012)

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