Answer:
b) 4,000,000
Step-by-step explanation:
Let the population is measured since 1995,
Given,
The initial population, P = 3,942,000,
Annual rate of growing, r = 0.7% = 0.007,
If y represents the population after t years
So, the population after t years would be,
Therefore, the population after 5 years,
Hence, the population in 2000 would be approximately 40,00,000.
Option 'b' is correct.
Step-by-step explanation:
jjsjdhhdhdhdhhfhdnjjdjdhshdsh
<span>supplement angles have sum = 180, complement angles have sum = 90
180-x = 4(90-x)
180-x = 360 -4x
3x = 180
x = 180/3
x = 60
answer </span><span>measure of the angle = 60</span><span>
</span>
B=number of ticets sold before
a=number of tickets sold after
cost of a ticket=number of tickets times cost per ticket
beforecost=39.95b
aftercost=54.95a
total cost=925000
39.95b+54.95a=925000
total number tickets=20000
b+a=20000
we have
39.95b+54.95a=925000
b+a=20000
multiply second equation by -39.95 and add to first equatin
39.95b+54.95a=925000
<u>-39.95b-39.95a=-799000 +</u>
0b+15a=126000
15a=126000
divide bot sides by 15
a=8400
sub back
b+a=20000
b+8400=20000
minus 8400 both sides
b=11600
11,600 tickets sold before
8400 tickets sold after
Answer:
A) Distance time graph
B) d(t) = 25t
C) The expression shows the distance more clearly.
Step-by-step explanation:
A) A distance time graph as seen in the attachment provides a representation of the distance travelled.
We are told the car travels at a constant speed of 100 meters per 4 seconds. Which means that 100 m for each 4 hours. So, for 200m, it's 8 hours like seen in the graph and for 300m,it's 12 hours as seen in the graph.
B) And expression for the distance is;
d = vt
Where;
d is distance in metres
v is speed in m/s and t is time
We are told that the car travels at a constant speed of 100 meters per 4 seconds.
Thus, v = 100/4 = 25 m/s
Distance travelled over time is;
d(t) = 25t
C) Looking at both A and B above, it's obvious that the expression of the distance shows a more clearer way of getting the distance because once we know the time travelled, we will just plug it into the equation and get the distance. Whereas, for the representation form, one will need to longer graphs if the time spent is very long.