Question

Find a degree 3 polynomial having zeros -1,2 and 7 and the coefficient of x^3 equal 1.

Answer 1

Answer:

$x^{3}-8x^{2} +5x+14$

Step-by-step explanation:

n=3

f(x) = (x-(-1))(x-2)(x-7)

=(x+1)(x-2)= $(x^{2} -x-2)$(x-7)=$x^{3}-8x^{2}+5x+14$