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Licemer1 [7]
3 years ago
7

HURRY PLEASE!!!!

Mathematics
2 answers:
dimulka [17.4K]3 years ago
6 0
N A) outcome in event which A and B out outcome in event of A and B which it’s n (A x n B probability of the outcomes in fundamental counting. Hope this helps with your question..
poizon [28]3 years ago
6 0

Answer: what the other person answered

Step-by-step explanation:

You might be interested in
How is basic math used in a business? Give me three examples.
anyanavicka [17]

Answer:

Understanding basic business math is necessary for profitable operations and accurate record keeping. Knowing how to add, subtract, multiply, divide, round and use percentages and fractions is the minimum you need to price your product and meet your budget.

4 0
3 years ago
You are creating a decorated rope that is at least 20 feet long to create a rope you are using beads that are 6 inches long writ
Nitella [24]

Answer:

The number of beads used must be at least 40 to make a decorated rope of at least 20 feet length. The inequality is:

6n\geq 240\\n\geq 40

Step-by-step explanation:

Let the number of beads used be 'n'.

Now, length of 1 bead = 6 in

∴ Length of 'n' beads = 6\times n=6n\ in

Now, minimum length of rope is 20 ft. Converting feet to inches, we get:

20\ ft =20\times 12=240\ in

Now, beads are inserted in the rope. So, the length of rope is same as the length of all the beads joined together.

As per question, length must be at least 20 ft or 240 in.

Therefore, the length of all beads joined together must be at least 240 inches. This gives,

6n\geq 240\\n\geq \frac{240}{6}\\n\geq 40

Therefore, the number of beads used must be at least 40 to make a decorated rope of at least 20 feet length.

5 0
4 years ago
Can someone help me? I'm lost.
KengaRu [80]
First step is to find R
use The equation QR =43

R=43/Q
now since we have R plug that into PR= 9x - 31

P(43\Q) = 9x - 31
P43/QP +31 =9x
9x=P43÷QP +31
x=P43÷QP+31 /9

Since the question doesnt specify to leave the question in terms of P or Q i suppose this is the final answer

Hope this helps! xD
would not mind if you put it as the brainliest answer
3 0
4 years ago
How many nanoseconds does it take for a computer to perform one calculation if it performs 6.7 × 10^{7} calculations per second?
crimeas [40]

Answer:

<u><em>the comuter does 1 calculation in 1.5*10^{-17} nanosec</em></u>

Step-by-step explanation:

<u><em>First step: we need to write all terms in nanosec, as we know:</em></u>

<u><em>1[nanosec]= 10^{-9}[sec]</em></u>

<u><em>The computer does 6.7*10^{7} [\frac{calculation}{sec}]</em></u>

<u><em>if we multiplicate for \frac{sec}{nanosec*10^{*9}}, from the units convertion.</em></u>

<u><em>6.7*10^{7} [\frac{calculation}{sec} * \frac{sec}{nanosec*10^{*9}}</em></u>

<u><em>6.7* 10^{16} [\frac{calculation}{nanosec}]</em></u>

<u><em>Now doing a simple three rule we have this:</em></u>

<u><em>6.7 * 10^{16} calculation in ⇒ 1 nanosec</em></u>

<u><em>1 calculation in ⇒ \frac{1 nanosec* 1calculation}{6.7*10^{16} calculation }</em></u>

<u><em>So, we found: the comuter does 1 calculation in 1.5*10^{-17} nanosec</em></u>

8 0
3 years ago
Please help! :) I appreciate it!!!
jarptica [38.1K]
C. It's the only one with a slope that's a negative reciprocal and the same intercept which us where they meet
4 0
3 years ago
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