Y-2x-1=0 for -2 ≤ x ≤ 4 . can someone help me graph a straight line for this pls ?
1 answer:
Answer: See the graph below.
It is a straight line segment with endpoints (-2,-3) and (4,9).
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Explanation:
We're told that x is between -2 and 4, including both endpoints.
Let's see what y is when we plug in x = -2
y-2x-1 = 0
y-2(-2)-1 = 0
y+4-1 = 0
y+3 = 0
y = -3
So x = -2 pairs up with y = -3. The point (x,y) = (-2,-3) is on the line. This is the left most endpoint.
Repeat for x = 4 to find what y must be
y-2x-1 = 0
y-2(4)-1 = 0
y-8-1 = 0
y-9 = 0
y = 9
Therefore the point (x,y) = (4,9) is also on the line. It's the right most endpoint
Once we have the two points, we can form the straight line. Simply connect the endpoints mentioned as shown below. We don't extend the line infinitely outwards in both directions because meaning x cannot be smaller than -2, and x cannot be greater than 4 either.
Side note: The given equation is the same as y = 2x+1. It has slope 2 and y intercept 1.
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Answer:
Triangles represented by option B are similar triangles.
Step-by-step explanation:
Please find the attachment.
We have been given 4 group of triangles and we are asked to find which group contains similar triangles.
A. We can see from our diagram that triangles provided in option A are not similar.
The first triangle is an isosceles right triangle as it has 2 angles each having measure 45 degrees. By angle sum property the measure of 3rd angle will be:
The second triangle is an equilateral triangle as all the sides equal to 7 units, so all angles will be equal to 60 degrees.
The 3rd triangle is an isosceles triangle as it has 2 angles each having measure 53 degrees. By angle sum property the measure of 3rd angle will be:
We can see that none of the triangles have same angle measures, therefore, option A is not a correct choice.
B. The triangles provided in option B are similar triangles as each triangle have one right angle and they are sharing the same vertex.
Let us assume that the common vertex has x degrees angle, then by angle sum property the measure of 3rd angle in each triangle will be degrees. Therefore, the triangles provided in option B are similar triangles by AAA similarity theorem.
C. The triangles provided in option C are not similar triangles as we are not told that the given lines are parallel or not. In addition the bottom figure is a quadrilateral as it has 4 angles, Therefore, the given triangles are not similar triangles.
D. We can see that our given triangles have vertical angles, so their measure will be 32 degrees. Since the given side lengths are different, therefore, this group of triangles is not similar.
