No, because the hypotenuse needs to be three. It would be true if the lengths were 2, 2, 4
Answer:
17 m
Step-by-step explanation:
As shown in the figure, 
is the ground level, 
is the old level of water which was at 20 m below ground level, 
is the new level of water which is 5m above of old level. The height of wall of the well, 1.20 m, and the the pelly at 80 cm =0.80 m, has been shown too.
The minimum length of the rope is equal to the distance between the pully and the new water level, indicated by the length 
in the figure.
So, 
Hence, Raghu must use a rope having the minimum length 17 m to draw water from the well.
Answer:
V = πr²h
S=2πrh
h= 2/3 millimeters
new height= 8/3 millimeters
S= 8π millimeters square
New surface area = 32π millimeters square
Step-by-step explanation:
The volume of the cylinder is given by V = πr²h where r is the radius and h is the height.
The surface area of the cylinder is given by S= 2πrh + 2πr²
Where πr² gives the area of the base and 2πr² gives the area of the top and bottom surfaces. The surface area S of a cylinder, not including the top and bottom of the cylinder, is therefore S=2πrh.
V = πr²h
96π= π (6*6) (h+2)
96 = 36 (h+2)
96/36= h+2
h= 96/36-2
h= 96-72/36
h= 24/36
h= 4/6
h= 2/3 millimeters
New height
h + 2= 2/3 + 2
= 2+6/3= 8/3 millimeters
Now S =2πrh
S = 2π(6) (2/3)
S= 8π millimeters square
New Surface area
S = 2π(6) (8/3)
S= 32π millimeters square
