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2 years ago

How many dessert combinations does Megan have? Just write the number in the space below

Mathematics

1 answer:

vlabodo [156]2 years ago

3 0

The answer is7 lodnsndbbd

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-5(3-r)=30<br> Please help!

Andrej [43]

The answer to -5(3-r)=30

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2 years ago

Solve for x. <br><br> x = ___

Mila [183]

Answer:

Solve y=x^2+2 for x.A.B.C.D

Step-by-step explanation:

sorry lamo

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2 years ago

Find the value of each variable

yanalaym [24]

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Step-by-step explanation:

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2 years ago

Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

$\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}$

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

$\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}$

$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

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3 years ago

What is the process 9.04 turning into 9.10?

Yuki888 [10]

You would add 0.06.

Hope This Helps You!
Good Luck Studying :)

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2 years ago