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olga_2 [115]
3 years ago
8

What is the volume of this cube PLZZZZZZZZZZ

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0

Answer:

1 cubic foot

Step-by-step explanation:

1*1*1 = 1

Anna35 [415]3 years ago
3 0

Answer:

6 maybe

Step-by-step explanation:

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Someone please help im so dumb
34kurt
You are not alone I am dumb too
8 0
3 years ago
HELP FAST
belka [17]

Answer: 1)

y < 0

x >= 0

2)

3x - 4y < 1

3x - 4y < 8

3) 4x + y > 4

8x + 2y < -5

4)

3x - y > 1

6x - 2y < 20

Step-by-step explanation:

7 0
2 years ago
The amount of coffee that a filling machine puts into an 8 dash ounce 8-ounce jar is normally distributed with a mean of 8.2 oun
Inessa [10]

Answer:

73.3% probability that the sampling error made in estimating the mean amount of coffee for all 8 dash ounce 8-ounce jars by the mean of a random sample of 100​ jars, will be at most 0.02​ ounce

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theore.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 8.2, \sigma = 0.18, n = 100, s = \frac{0.18}{\sqrt{100}} = 0.018

What is the probability that the sampling error made in estimating the mean amount of coffee for all 8 dash ounce 8-ounce jars by the mean of a random sample of 100​ jars, will be at most 0.02​ ounce

That is, probability of the sample mean between 8.2-0.02 = 8.18 and 8.2 + 0.02 = 8.22, which is the pvalue of Z when X = 8.22 subtracted by the pvalue of Z when X = 8.18.

X = 8.22

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.22 - 8.2}{0.018}

Z = 1.11

Z = 1.11 has a pvalue of 0.8665.

X = 8.18

Z = \frac{X - \mu}{s}

Z = \frac{8.18 - 8.2}{0.018}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335.

0.8665 - 0.1335 = 0.7330

73.3% probability that the sampling error made in estimating the mean amount of coffee for all 8 dash ounce 8-ounce jars by the mean of a random sample of 100​ jars, will be at most 0.02​ ounce

6 0
3 years ago
Trigonometry, just the first one, will mark as brainliest if helpful
jek_recluse [69]

Answer:

a = -0.5

b = −1.73

c = −0.70

d = -\frac{\sqrt{2} }{2} ≈ -0.70710678

Step-by-step explanation:

EXPLAIN Q(a):

sin(−30)

Use the property sin(−x)=−sin(x).

−sin(30)

Get the value of sin(30) from trigonometric values table.

-0.5

5 0
3 years ago
Find the sum of the first 20terms of this arithmetic progression: 2,5,8,11,.......​
postnew [5]
Y = -1 + 3x... y1= 2, y2=5... so the 20th term will be 59. There will be ten pairs (i.e 2,59 equal 61... 5,56 equal 61) so multiply this 61 by 10 and your sum will be 610
8 0
3 years ago
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