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3 years ago

Someone please help im so dumb

Mathematics

1 answer:

34kurt3 years ago

8 0

You are not alone I am dumb too

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For the sequence an = an-1 + an-2 and ai = 2, a2 = 3,

loris [4]

Answer:

$a_1 = 2$

$a_2 = 3$

$a_3 = 5$

$a_4 = 8$

$a_5 = 13$

Step-by-step explanation:

Given

$a_n = a_{n-1} + a_{n-2}$

$a_1 = 2$

$a_2 = 3$

Solving (a): The first term

This has already been given as:

$a_1 = 2$

Solving (b): The second term

This has already been given as:

$a_2 = 3$

Solving (c): The third term

This is calculated as:

$a_n = a_{n-1} + a_{n-2}$

$a_3 = a_{3-1} +a_{3-2}$

$a_3 = a_2 +a_1$

$a_3 = 3 +2$

$a_3 = 5$

Solving (d): The fourth term

This is calculated as:

$a_n = a_{n-1} + a_{n-2}$

$a_4 = a_{4-1} +a_{4-2}$

$a_4 = a_3 +a_2$

$a_4 = 5+3$

$a_4 = 8$

Solving (e): The fifth term

This is calculated as:

$a_n = a_{n-1} + a_{n-2}$

$a_5 = a_{5-1} +a_{5-2}$

$a_5 = a_4 +a_3$

$a_5 = 8+5$

$a_5 = 13$

3 0

3 years ago

Picture is below...........................

liubo4ka [24]

Answer:

C or A

thats all i know hope it helps

4 0

3 years ago

What is the 7th term of the geometric sequence where a1 = -5 and a5 = -1,280?

8_murik_8 [283]

Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number.

Here we are give the initial term so we have to solve to solve for the common ratio...

a(5)=-1280 and a(1)=-5 so

-1280=-5r^(5-1)

-1280=-5r^4

256=r^4

256^(1/4)=r

4=r, so our sequence is:

a(n)=-5(4^(n-1)), so the 7th term is:

a(7)=-5(4^6)

a(7)= -20480

3 0

3 years ago

Https://brainly.com/question/19893840

Tems11 [23]

Answer:

umm what

Step-by-step explanation:

3 0

3 years ago

A circle has a diameter with endpoints at –2 + i and –6 –11i. What is the center of the circle?

kotykmax [81]

Be more specific. Like what is it asking you to do ? I'm trying to help. :)

4 0

4 years ago