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lesya [120]
3 years ago
11

Write the equation of the line that passes through (-3,5) and (2, 10) in slope-intercept form.

Mathematics
1 answer:
cupoosta [38]3 years ago
7 0

Answer:

y=x+8

Step-by-step explanation:

Slope of straight line can be calculated as

m=\frac{y_2-y_1}{x_2-x_1}

Here (x_1, y_1)=(-3, 5) \ and \ (x_2, y_2) = (2, 10)

m =\frac{10-5}{2-(-3)}\\m=1

Equation of straight line in slope intercept form is

y-y_1=m(x-x_1)\\y-5=(x+3)

y=x+8

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Answer:

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Step-by-step explanation:

Given:

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\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{3}(x-\stackrel{x_1}{(-3)}) \\\\\\ y+7=3(x+3)\implies y+7=3x+9\implies y = 3x+2

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