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Oksanka [162]
3 years ago
9

Answer equation in photo, show work please and thanks

Mathematics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

19

Step-by-step explanation:

There are 38 points total, each field goal is 2 points.

If we do 38/2 we get 19.

Image has work...

\frac{38}{2}

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-7x - 12 = - 7х + 3(-4 - x)
dsp73

Answer:

x=0

Step-by-step explanation:

-7x - 12 = - 7x + 3(-4 - x)

Open up the parentheses

-7x - 12 = - 7x -12-3x

-7x cancels out on both sides

-12 =-12-3x

-12 cancels out on both sides

0=-3x\\x=0

I hope this helps!

4 0
3 years ago
Dadas las funciones f(x) = x + 3, g(x)= x(cuadrada)+ 5x + 6,r(x) = x+2, s(x) = x(cuadrada) - 3x - 10
Aleksandr [31]
So the answer is D hope this would help you

5 0
3 years ago
Could someone please explain how to solve for the area?
mixas84 [53]

9514 1404 393

Answer:

  779.4 square units

Step-by-step explanation:

You seem to have several problems of this type, so we'll derive a formula for the area of an n-gon of radius r.

One central triangle will have a central angle of α = 360°/n. For example, a hexagon has a central angle of α = 360°/6 = 60°. The area of that central triangle is given by the formula ...

  A = (1/2)r²sin(α)

Since there are n such triangles, the area of the n-gon is ...

  A = (n/2)r²sin(360°/n)

__

For a hexagon (n=6) with radius 10√3, the area is ...

  A = (6/2)(10√3)²sin(360°/6) = 450√3 ≈ 779.4 . . . . square units

8 0
3 years ago
Read 2 more answers
Use mathematical induction to show that 4^n ≡ 3n+1 (mod 9) for all n equal to or greater than 0
cestrela7 [59]
When n=0, you have

4^0=1\equiv3(0)+1=1\mod9

Now assume this is true for n=k, i.e.

4^k\equiv3k+1\mod9

and under this hypothesis show that it's also true for n=k+1. You have

4^k\equiv3k+1\mod9
4\equiv4\mod9
\implies 4\times4^k\equiv4(3k+1)\mod9
\implies 4^{k+1}\equiv12k+4\mod9

In other words, there exists M such that

4^{k+1}=9M+12k+4

Rewriting, you have

4^{k+1}=9M+9k+3k+4
4^{k+1}=9(M+k)+3k+3+1
4^{k+1}=9(M+k)+3(k+1)+1

and this is equivalent to 3(k+1)+1 modulo 9, as desired.

3 0
4 years ago
What is the value of (5^3)^1=? without any exponents.
hodyreva [135]

Answer:

the answer is 125

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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