Answer:
Frequency of allele A1- 0.41
Explanation:
In Hardy weinberg equilibrium,
P refers to the dominant allele
q refers to the recessive allele
The allele frequency will be p+q=1
The genotypic frequency is- P²+q²+2pq=1
P²= genotype of dominant trait ( A1A1)- 77
2pq= genotype of heterozygotes (2pq)- 65
q²= genotype of recessive trait (A2A2)- 123
Total number of offsprings= 77+ 65+ 123
= 265
Now to calculate allele frequency of A1=
= 77/265 + 1/2( 65//265)
= 0.290+ 0.122
= 0.413
Thus, 0.41 is correct.
It would be 1,800 to 2,40p
Cephalization describes the process by which organisms develop a distinct head. The head of a cephalized organism contains a concentrated group of nerves, or brain, that controls the rest of the organism, as well as specialized organs for consumption and perception, like mouths, eyes and ears. Cephalized organisms exhibit a distinct division between parts of the body; they have a front, back, top and bottom. These animals comprise the bulk of animals that are encountered on a daily basis.
sea star following organisms exhibits cephalization
Answer:
This was the only treatment options adopted for the Ebola in 1995 in the Democratic Republic of Congo. The assumption was that immune response is generated by the virus in the WBC of the infected individuals. These response produce antibodies.
A total if 8 patients were transfused with these blood contained antibodies, but one of these died, the remaining 7 patients survived.
The antibodies were believed to have multiplied(produced b-cells) to neutralize the Ebola virus(antigens) and to ensure the survival of the patients
Explanation:
