Question

A black chicken and a white chicken are crossed. What is the probability that they will have erminette chicks?

Answer 1

Answer:

$Probability = 100\%$

Explanation:

Given

Crossing of a black chicken and a white chicken

Required

The probability of having erminette chicks

The genotype of a black chicken is represented as: BB

The genotype of a white chicken is represented as: WW

The genotype of an erminette chicken is represented as: BW

Using a Punnett square, we have:

$\begin{array}{ccc}{} & {B} & {B} & {W} & {BW} & {BW} & {W} & {BW} & {BW}\ \end{array}$

The result of crossing the two chicken gives 4 BW out of a total of 4

i.e 4 erminette chickens out of 4 possible chickens

So, the probability is:

$Probability = \frac{4}{4}$

$Probability = 1$

Represent as percentage:

$Probability = 100\%$