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3 years ago

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For spirit week at a local high school, students were encouraged to wear their school colors of green and white. 1,200 students

wore their school colors while 300 students did not wear green and white. What percent of the school population did NOT wear their school colors?

1 answer:

Dimas [21]3 years ago

5 0

Answer:

20%

Step-by-step explanation:

add 1200 and 300 to get the total amount of students at the school
the you will place 300 over 1500(the total) and multiply it by 100
ans= 20%

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Answer:

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Step-by-step explanation:

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A probability experiment is conducted in which the sample space of the experiment is S 1,2,3,4, 5,6,7,8, 9, 10, 11, 12]. Let eve

Alenkinab [10]

Answer:

$E\ n\ F = \{1, 5, 6,7\}$

$F\ n\ G =\{9\}$

$F\ U\ G =\{1,5,6, 7, 8,9,10, 11, 12\}$

$P(F\ U\ G) = \frac{3}{4}$

Step-by-step explanation:

Given

$S = \{1,2,3,4, 5,6,7,8, 9, 10, 11, 12\}$

$E = \{1,2, 3, 4, 5, 6,7\}$

$F =\{1,5,6, 7, 8,9\}$

$G = \{9,10, 11, 12\}$

$H = \{2, 3, 4\}$

Solving (5): E and F

Sets of E and F = E n F

$E\ n\ F = \{1,2, 3, 4, 5, 6,7\}\ n\ \{1,5,6, 7, 8,9\}$

List out common elements

$E\ n\ F = \{1, 5, 6,7\}$

<em>They are not mutually exclusive because </em> $n(E\ n\ F) \neq 0$ <em />

Solving (6): F and G

Sets of F and G = F n G

$F\ n\ G =\{1,5,6, 7, 8,9\}\ n\ \{9,10, 11, 12\}$

List out common elements

$F\ n\ G =\{9\}$

<em>They are not mutually exclusive because </em> $n(F\ n\ G) \neq 0$ <em />

Solving (7): F or G and P(F or G)

Sets of F or G = F U G

$F\ U\ G =\{1,5,6, 7, 8,9\}\ U\ \{9,10, 11, 12\}$

List all elements without repetition

$F\ U\ G =\{1,5,6, 7, 8,9,10, 11, 12\}$

Solving P(F U G)

$P(F\ U\ G) = \frac{n(F\ U\ G)}{n(S)}$

$n(F\ U\ G) = 9$

$n(S) = 12$

Hence;

$P(F\ U\ G) = \frac{9}{12}$

Divide by 3

$P(F\ U\ G) = \frac{3}{4}$

6 0

3 years ago