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Anon25 [30]
3 years ago
9

Can anybody helppp meee please

Mathematics
1 answer:
crimeas [40]3 years ago
3 0

Answer:

r^2=(A/pi)

Step-by-step explanation:

if A=pi*r^2 then maybe dividing by pi to get r^2 alone says r^2=(A/pi) or to get rid of the exponent you may square root each side so r=(sqrt(A/pi))

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Which would be the best name for a function that takes the time of day and returns the numbers of coffee sold at a coffee shop?
konstantin123 [22]

Answer:

Coffee(time)

Step-by-step explanation:

A function's output variable will be:

output(input)

So we need to find the input variable and the output variable.

We know that when the time of day changes, we get a certain amount of coffee sold. This means that the amount of coffee sold is directly influenced by the time of day.

The time of day then becomes our input as the coffee sold relies on that number.

That leaves coffee sold as our output!

So the best name for a function in this scenario is Coffee(time).

Hope this helped!

3 0
3 years ago
Which of the statements below best describes direct variation?
REY [17]
Direct variation is when one variable changes the other changes in proportion of the first, therefore all the above 
8 0
3 years ago
Refer to the figure to complete the proportion A/C = Y/?
salantis [7]
Hello,
Please, see the attached file.
Thanks.

3 0
3 years ago
Writeanequationforthelinethatpassesthrough(4,-3)and has a slope of 3.
djyliett [7]

Answer:

x+y=1 (if x=4 )

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7 0
2 years ago
Read 2 more answers
Help please! Will pick the Brainliest.<br> (sorry if it’s sideways)
KatRina [158]

1.

(x^2y^8)^\frac{2}{3}=x^{2\cdot\frac{2}{3}}y^{8\cdot\frac{2}{3}}=x^{\frac{4}{3}}y^{\frac{16}{3}}=x^{1\frac{1}{3}}y^{5\frac{1}{3}}=x^1x^\frac{1}{3}y^5y^\frac{1}{3}=xy^5\sqrt[3]{x}\sqrt[3]{y}=\boxed{xy^5\sqrt[3]{xy}}

Answer B)

2.

\frac{1}{3}\left(\frac{2}{15}x-\frac{2}{3}\right)>x+\frac{1}{5}\quad|\cdot3\\\\\\\frac{2}{15}x-\frac{2}{3}>3x+\frac{3}{5}\quad|\cdot15\\\\\\2x-\frac{30}{3}>45x+\frac{45}{5}\\\\2x-10>45x+9\\\\-10-9>45x-2x\\\\-19>43x\quad|:43\\\\\boxed{x

Answer B)

3.

\sqrt{14xy}\cdot\sqrt{12}\cdot\sqrt{30y}=\sqrt{14\cdot12\cdot30}\cdot\sqrt{xy^2}=\sqrt{2\cdot7\cdot3\cdot4\cdot2\cdot3\cdot5}\cdot\sqrt{xy^2}=\\\\=\sqrt{2^2\cdot3^2\cdot2^2\cdot5\cdot7}\cdot\sqrt{xy^2}=2\cdot3\cdot2\cdot\sqrt{35}\cdot y\cdot\sqrt{x}=\boxed{12y\sqrt{35x}}

3 0
3 years ago
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