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goldfiish [28.3K]
2 years ago
7

What does 15,660 estimate to

Mathematics
1 answer:
IrinaVladis [17]2 years ago
8 0

Answer:

16,700 is what it estimates to.

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What is the simplified form of 30 times x to the sixth power over 14 times y to the fifth power times the fraction 7 times y-squ
Sonbull [250]
If we convert the given in its mathematical form, we have,

                      (30x⁶/14y⁵)(7y²/6x⁴)
It can be observed that the numerator of the first and the denominator of the second have a common factor of 6x⁴. Also, the denominator of the first and the numerator of the second expression have a common factor of 7y².

                      ((6x⁴)(5x²)/(7y²)(2y³))(7y²/6x⁴)

Cancellation of the common terms will give us an answer of,
  
                               <em>5x²/2y³

</em>
<em />Therefore, the simplified version of the involved operation is 5x²/2y³. <em>
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6 0
3 years ago
Equivalent ratios<br>Select two ratios that are equivalent to 3 : 12.<br>Choose 2 answers:​
kipiarov [429]

Answer:

1:4 and 6:24

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
How to find n in 38n4​
Rus_ich [418]

Answer:

Step-by-step explanation:

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5 0
2 years ago
The Taylors have recorded their weekly grocery expenses for the past 12 weeks and determined that the mean weekly expense was ​$
SVETLANKA909090 [29]

Answer:

$84.80

Step-by-step explanation:

find the difference between accurate price and written price: 74 - 47 = 27

find written total (before Mrs. Taylor found mistake) by undoing the mean calculation: 82.55 x 12 = $990.60

the total expenses is $27 more than what they thought: 990.60 + 27 = 1017.60

divide accurate total by 12 to find mean: 1017.60 / 12 = $84.80

hope this helps :)

4 0
2 years ago
Can you help me? Please
Anni [7]

9514 1404 393

Answer:

  a.

Step-by-step explanation:

For an even-index radical, ...

  \sqrt[n]{x^n}=|x|\qquad\text{n even}

This lets us simplify the given expression as follows:

  \sqrt[4]{81x^6y^4}-|y|\sqrt[4]{x^6}-\sqrt[4]{16x^2}=\sqrt[4]{(3xy)^4x^2}-|y|\sqrt[4]{x^4x^2}-\sqrt[4]{2^4x^2}\\\\=3|xy|\sqrt[4]{x^2}-|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}=\boxed{2|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}}

4 0
2 years ago
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