Let the cost of one cup of hot chocolate be = x
Let the cost of one cup of hot tea be = y
Paul paid $ 25.50 for 3 cups of hot chocolate and 4 cups of tea.
Equation becomes =
...(1)
As given, the cost of each cup of tea was 2/3 the cost of each cup of hot chocolate.
.... (2)
Putting the value of y from (2) in (1)

=
=
=
x=4.5

=
y =3
Hence each cup of hot chocolate is $4.50
Each cup of tea is $3.
Answer:
(x-3)(x^2-7) = x^3 -3x^2 -7x + 21
just change the sign of the root and put x in front of it, then multiply the factors all together
(x-3)(x-sqr7)(x+sqr7) roots come in conjugate pairs to eliminate irrational coefficients
(x-sqr7)(x+sqr7) = x^2-7. similar to (a-b)(a+b) = a^2-b^2
Step-by-step explanation:
$0.80 = 1 pound
5.5 pounds in total
5.5x$0.80= $4.40
brainliest answer ?
Taking them at breakfast, lunch, and dinner
Answer: C = 7.62
You can verify this answer using this calculator.
7^2 + 3^2 = 58
√58 = 7.62