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2 years ago

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The graph of a linear function is shown on the coordinate grid. (TEKS 8.4C-R) What is the y-intercept of the graph of the linear

function?

1 answer:

Juliette [100K]2 years ago

5 0

3

The y axis intercepts the linear function at positive 3

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WORTH 60 POINTS! PLZ HELP! BRAINLIEST OPPORTUNITY!

makkiz [27]

Answer:

x = 10

Step-by-step explanation:

2) -3x + 17 = -x - 3

4) 20 = 2x

1) -3x + 12 + 5 = -x -3

5) 10 = x

3) 17 = 2x - 3

<u>-3(x - 4) + 5 = -x - 3</u>

<u>-3x + 12 + 5 = -x - 3</u>

<u>-3x + 17 = -x -3</u>

<em>+3x +3x</em>

<u>17 = 2x - 3</u>

<em>+3 + 3</em>

<u>20 = 2x</u>

<u>10 = x</u>

<u />

I hope that this helps! :)

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2 years ago

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agasfer [191]

Answer:

102

Step-by-step explanation:

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2 years ago

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igomit [66]

Answer: y+5= -1/7(x-7)

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3 years ago

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kkurt [141]

Answer:

0 to 4.5

Step-by-step explanation:

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3 years ago

An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individ

Tema [17]

Answer:

a) P=0.558

b) P=0.021

Step-by-step explanation:

We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.

The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

$P(x=k)=\frac{\lambda^ke^{-\lambda}}{k!} =\frac{4^ke^{-4}}{k!}$

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

$P(4\leq x\leq 9)=\sum_{k=4}^9P(k)\\\\\\ P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\P(9)=4^{9} \cdot e^{-4}/9!=262144*0.0183/362880=0.013\\\\\\$

$P(4\leq x\leq 9)=\sum_{k=4}^9P(k)=0.195+0.156+0.104+0.060+0.030+0.013=0.558$

b) The approximate probability that at least 9 carry the gene is:

$P(x\geq9)=1-P(x\leq 8)\\\\\\$

$P(0)=4^{0} \cdot e^{-4}/0!=1*0.0183/1=0.018\\\\P(1)=4^{1} \cdot e^{-4}/1!=4*0.0183/1=0.073\\\\P(2)=4^{2} \cdot e^{-4}/2!=16*0.0183/2=0.147\\\\P(3)=4^{3} \cdot e^{-4}/3!=64*0.0183/6=0.195\\\\P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\$

$P(x\geq9)=1-P(x\leq 8)\\\\P(x\geq9)=1-(0.018+0.073+0.147+0.195+0.195+0.156+0.104+0.060+0.030)\\\\P(x\geq9)=1-0.979=0.021$

8 0

2 years ago